Step-by-step explanation:
Below is an attachment containing the solution.
I believe it’s graph c :)
Answer:



[since in third quadrant cos 30=-![\frac{\sqrt{3}}{2}]](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%5D)

:150°or 
<u>150°</u><u>or</u><u> </u>
<u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
Answer:
29m+37?
Step-by-step explanation:
<em>Pemdas</em>
5m+3(8m+7)+4^2
Parentheses first: 5m+24m+21+4^2
Exponents next: 5m+24m+21+16
No multiplication or division so addition is last:
29m+37
These two can't add together because one has a variable.
Answer:
The number of hot beverages sold were 45 and the number of cold beverages sold were 180.
Step-by-step explanation:
Let the number of cold beverages sold be 
And the number of hot beverages sold be 
According to the question:
c=4
h...
1.5
c + 2
h = Sale of any day
Part1:
For Saturday.
The sale is of
360
then
1.5
c +
2
h =
360
Part 2:
Following the method of substitution.
And plugging the values of c=4
h...in equation where the sales of Saturday is given.
1.5
c + 2
h =360
1.5
4
h + 2
h =360
6
h + 2
h= 360
8
h=360
Dividing both sides with 8.
h=
h=45
Inserting h=45 in c=4
h...
we have c=4
45 = 180
So the number of hot beverages sold were 45 and the number of cold beverages sold were 180.