Given a polynomial 
and a point 
, we have that
We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of
Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be
To fix the correct value for a, we impose 
:
And so we must impose
So, the function we're looking for is
B. A smaller percentage of second-lunch students (38%) eat outside.
Answer:
cosjk = √55 i/3
tanjk = 8/√55 i
Step-by-step explanation:
Given
sin jk = 8/3
According to SOH CAH TOA
Sin theta = opposite/hypotenuse = 8/3
Opposite = 8
hypotenuse = 3
Get the adjacent using the pythagoras theorem
hyp² = opp²+adj²
adj² = hyp² - opp²
adj² = 3² - 8²
adj² = 9-64
adj² = -55
adj = √-55
adj = √55 i (i = √-1)
Get cosjk
cosjk = adj/hyp
cosjk = √55 i/3
Get tanjk
tanjk = opp/adj
tanjk = 8/√55 i
40%
40 percent of 25 is 10
10/25x100 and you will get your answer which is 40
Answer:
5083
Step-by-step explanation:
6^3 + 5(8 + 15)
Simplify the bracket first
6 x 6 x 6 + 5 (23)
216 + 5 (23)
221 (23)
221 x 23 = 5083
