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Ivahew [28]
3 years ago
6

For students who first enrolled in two year public institutions in a recent​ semester, the proportion who earned a​ bachelor's d

egree within six years was 0.395. The president of a certain college believes that the proportion of students who enroll in her institution have a higher completion rate. ​(a) Determine the null and alternative hypotheses.
Mathematics
1 answer:
kondaur [170]3 years ago
6 0

Answer:

Null hypothesis =  H_0:p=0.395

Alternate hypothesis =H_a:p>0.395

Step-by-step explanation:

Given : In a recent​ semester, the proportion who earned a​ bachelor's degree within six years was 0.395.

The president of a certain college believes that the proportion of students who enroll in her institution have a higher completion rate.

To Find : Determine the null and alternative hypotheses.

Solution:

In a recent​ semester, the proportion who earned a​ bachelor's degree within six years was<u> 0.395. </u>

Claim : the proportion of students who enroll in her institution <u>have a higher completion rate.</u>

So,null hypothesis =  H_0:p=0.395

Alternate hypothesis =H_a:p>0.395

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Section 5.2 Problem 19:
rjkz [21]

Answer:

y(x)=2xe^{3x} (See attached graph)

Step-by-step explanation:

To solve a second-order homogeneous differential equation, we need to substitute each term with the auxiliary equation am^2+bm+c=0 where the values of m are the roots:

y''-6y'+9y=0\\\\m^2-6m+9=0\\\\(m-3)^2=0\\\\m-3=0\\\\m=3

Since the values of m are equal real roots, then the general solution is y(x)=C_1e^{m_1x}+C_2xe^{m_1x}.

Thus, the general solution for our given differential equation is y(x)=C_1e^{3x}+C_2xe^{3x}.

To account for both initial conditions, take the derivative of y(x), thus, y'(x)=3C_1e^{3x}+C_2e^{3x}+3C_2xe^{3x}

Now, we can create our system of equations given our initial conditions:

y(x)=C_1e^{3x}+C_2xe^{3x}\\ \\y(0)=C_1e^{3(0)}+\frac{C_2}{6}(0)e^{3(0)}=0\\ \\C_1=0

y'(x)=3C_1e^{3x}+C_2e^{3x}+3C_2xe^{3x}\\\\y'(0)=3C_1e^{3(0)}+C_2e^{3(0)}+3C_2(0)e^{3(0)}=2\\\\3C_1+C_2=2

We then solve the system of equations, which becomes easy since we already know that C_1=0:

3C_1+C_2=2\\\\3(0)+C_2=2\\\\C_2=2

Thus, our final solution is:

y(x)=C_1e^{3x}+C_2xe^{3x}\\\\y(x)=2xe^{3x}

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