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patriot [66]
3 years ago
10

Anthony has a cup full of nickels and dimes that he would like to put in his savings account. When he takes the cup to the bank,

the banker tells him that the 566 coins in the cup are worth $43.80. Which of the following systems of equations models the coins in Anthony’s cup? Let n represent nickels, and d represent dimes.
Mathematics
2 answers:
jenyasd209 [6]3 years ago
8 0

Answer:

n+d=566

0.05n+0.10d=43.80

Step-by-step explanation:

Let nickels be represented by = n

Let dimes be represented by = d

Total number of coins in the cup = 566

So, first equation becomes :

n+d=566

The total value of coins is = $43.80

So, second equation becomes :

0.05n+0.10d=43.80

The equations are not given to choose from, but these are the equations that form according to given situation.

Rus_ich [418]3 years ago
5 0
The answer would be 566\43.80 is 12.9223744292
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13.41 x (5.4 divided by 9)
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The value of the expression will be 8.166.

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Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The mathematical expression is,

⇒ 13.41 x (5.4 divided by 9)

Now,

Solve the expression as;

⇒ 13.41 x (5.4 divided by 9)

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1 year ago
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3 years ago
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Simply the attached question​
Finger [1]

Answer:

=x⁴−x³−14x²

Step-by-step explanation:

<h3>Let's simplify step-by-step.</h3>

x²(3x²+5x−4)−2x²(x²+3x+5)

<h3>Distribute:</h3>

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2 years ago
How to turn 1/4 divided by 6 into multiplication equation
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Answer:

1/4 × 1/6

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3 years ago
How to find the length of a triangle with only one side non right triangle?
castortr0y [4]
The trigonometry of non-right triangles

So far, we've only dealt with right triangles, but trigonometry can be easily applied to non-right triangles because any non-right triangle can be divided by an altitude* into two right triangles.

Roll over the triangle to see what that means →



Remember that an altitude is a line segment that has one endpoint at a vertex of a triangle intersects the opposite side at a right angle. See triangles.

Customary labeling of non-right triangles

This labeling scheme is comßmonly used for non-right triangles. Capital letters are anglesand the corresponding lower-case letters go with the side opposite the angle: side a (with length of a units) is across from angle A (with a measure of A degrees or radians), and so on.



Derivation of the law of sines

Consider the triangle below. if we find the sines of angle A and angle C using their corresponding right triangles, we notice that they both contain the altitude, x.



The sine equations are



We can rearrange those by solving each for x(multiply by c on both sides of the left equation, and by a on both sides of the right):



Now the transitive property says that if both c·sin(A) and a·sin(C) are equal to x, then they must be equal to each other:



We usually divide both sides by ac to get the easy-to-remember expression of the law of sines:



We could do the same derivation with the other two altitudes, drawn from angles A and C to come up with similar relations for the other angle pairs. We call these together the law of sines. It's in the green box below.

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two sides and an angle not between them ortwo angles and a side not between them.

Law of Sines



Examples: Law of sines

Use the law of sines to find the missing measurements of the triangles in these examples. In the first, two angles and a side are known. In the second two sides and an angle. Notice that we need to know at least one angle-opposite side pair for the Law of Sines to work.

Example 1

Find all of the missing measurements of this triangle:




The missing angle is easy, it's just



Now set up one of the law of sines proportions and solve for the missing piece, in this case the length of the lower side:



Then do the same for the other missing side. It's best to use the original known angle and side so that round-off errors or mistakes don't add up.



Example 2

Find all of the missing measurements of this triangle:




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Now it's easy to calculate the third angle:



Then apply the law of sines again for the missing side. We have two choices, we can solve



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Derivation of the law of cosines

Consider another non-right triangle, labeled as shown with side lengths x and y. We can derive a useful law containing only the cosine function.



First use the Pythagorean theorem to derive two equations for each of the right triangles:



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We could again do the same derivation using the other two altitudes of our triangle, to yield three versions of the law of cosines for any triangle. They are listed in the box below.

Law of Cosines

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Examples: Law of cosines

Use the law of cosines to find the missing measurements of the triangles in these two examples. In the first, the measures of two sides and the included angle (the angle between them) are known. In the second, three sides are known.


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