Pretty sure B would be the answer
Answer:
d. 1/3
Explanation:
Given, M is a dominant allele which is responsible for tailless kittens and m is recessive wild type allele which leads to kittens with tail. M is a lethal allele which means that if it is present in homozygous condition, the kitten will not survive. So the Manx cats should be heterozygous i.e. Mm.
When they mate, Mm X Mm :
M m
M MM Mm
m Mm mm
1/4 kittens will have MM genotype so they will not survive. Out of the remaining kittens, 1/3 will be mm and hence they will have normal tail. Remaining 2/3 will have Mm genotype like their parents and will be born without tail. Hence, there is 1/3 probability that one of the four kittens will have a normal tail.
<h2>GAC</h2><h3>I'm assuming you're talking about DNA base pairs?</h3>
Trees and flowers I might be wrong i don’t know let me know if I’m right
Increased grazing of oxen and cattle
