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2 years ago

9

Which agency is in charge of printing money?

1 answer:

kherson [118]2 years ago

7 0

Answer: Tresury department

Step-by-step explanation:

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The perimeter of a rectangle is 42 inches. If the width of the rectangle is 6 inches, what is the length?

snow_lady [41]

Answer:

7

Step-by-step explanation:

8 0

2 years ago

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Jerry has a credit card debt of $15,600 that he would like to reduce by applying $8500 of his inheritance money to the balance

aev [14]

Answer:

Jerry would still be in debt by 7100

Step-by-step explanation:

Just subtract 8500 from 15600

6 0

1 year ago

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

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Which of the following expressions is not equivalent to <br> 2(b+8)?

maksim [4K]

the awser is (-2)(8 + 6) + (-3)

7 0

2 years ago

Divide 36x^3-96x^2+48x by 12x

sergij07 [2.7K]

Answer:

3x^2 - 8x + 4.

Step-by-step explanation:

36x^3 - 96x^2 + 48x

Dividing by 12 term by term:

= 3x^2 - 8x + 4.

5 0

3 years ago

Read 2 more answers