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SVEN [57.7K]
3 years ago
10

How do I do this? Thank you!

Mathematics
2 answers:
labwork [276]3 years ago
8 0

Answer:

D

Step-by-step explanation:

\frac{5}{5^{\frac{1}{3} } } =5^1*5^{\frac{-1}{3} } =5^{1-\frac{1}{3} } =5^{-\frac{2}{3} } =\frac{1}{5^{\frac{2}{3} } } =\frac{1}{(5^{2}) ^{\frac{1}{3} } } =\frac{1}{\sqrt[3]{25} }

saveliy_v [14]3 years ago
6 0
Can you post a more clear picture
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Simplify 5m-2(6m-5)+2<br><br>a. -7m-8<br>b. -7m+12<br>c. 17m+12<br>d. 17m-8
fgiga [73]

The answer is B. -7m+12.


First distribute the -2 to 6m and -5.

5m-2(6m-5)+2

5m+(-2*6m)+(-2*-5)+2

5m+-12m+10+2


After that, combine the like terms.

5m+-12m+10+2

-5m+-12m=-7m

10+2=12


The simplified expression is -7m+12.

7 0
3 years ago
How to calculate the rise and run of a slope (4,-1) and (-2,3)
astra-53 [7]
m =  \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }
m =   \frac{3 - (-1)}{-2 - 4}
m =  \frac{4}{2}
m = 2
8 0
3 years ago
I need help solving a system of linear equation, and it says to solve it by Substitution.
olga_2 [115]
2x - 3y = -24
x+ 6y = 18

you solve the first one by the x:

2x = -24 + 3y

x = (-24+3y)/2

then you substitute what you found in the other equation and you solve by y

(-24+3y)/2 + 6y = 18                   multiply everything by 2

-24 + 3y + 12y = 36

3y + 12y = 36 + 24

15y = 60

y = 60/15

y = 4

Good job! You found your y! :D

Now let's substitute the y in the first equation with 4:

2x - 3(4) = -24

2x - 12 = -24

2x = -24 + 12

2x = -12

x = -12/2

x= -6

Done!! ;) <span />
6 0
3 years ago
Read 2 more answers
I need help with this question please I’ll give u brain
lina2011 [118]

Answer:2In2-2In3

Step-by-step explanation:

In(4/9)

In4-In9

In2^2-In3^2

2In2-2In3

7 0
3 years ago
Suppose that a die is rolled twice. What are the possible values that the following random variables can take on:(a) the maximum
andreyandreev [35.5K]

Answer and explanation:

Given : Suppose that a die is rolled twice.

The sample space form is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

To find : What are the possible values that the following random variables can take on

(a) The maximum value to appear in the two rolls;

The possible values are 1; 2; 3; 4; 5; 6.

b) The minimum value to appear in the two rolls;

The possible values are 1; 2; 3; 4; 5; 6.

c) The sum of the two rolls;

The possible values are 2; 3; 4; 5; 6; 7; 8; 9; 10; 11; 12.

d) The value of the first roll minus the value of the second roll.

The possible values are -5; -4; -3; -2; -1; 0; 1; 2; 3; 4; 5.

5 0
3 years ago
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