3 years ago

How do I do this? Thank you!

Mathematics

2 answers:

labwork [276]3 years ago

8 0

Answer:

Step-by-step explanation:

$\frac{5}{5^{\frac{1}{3} } } =5^1*5^{\frac{-1}{3} } =5^{1-\frac{1}{3} } =5^{-\frac{2}{3} } =\frac{1}{5^{\frac{2}{3} } } =\frac{1}{(5^{2}) ^{\frac{1}{3} } } =\frac{1}{\sqrt[3]{25} }$

saveliy_v [14]3 years ago

6 0

Can you post a more clear picture

You might be interested in

Can I get help with this pls

LuckyWell [14K]

Answer:

Step-by-step explanation:

7 0

3 years ago

8 ^ x * 16 ^ x - 1 equals 1

Lana71 [14]

Answer:

${8}^{x} \times {16}^{x } - 1 = 1 \\ {2}^{3x} \times {2}^{4x} = 1 + 1 \\ {2}^{7x} = {2}^{1} \\ 7x = 1 \\ x = \frac{1}{7}$

7 0

3 years ago

#12 with explanation please

4vir4ik [10]

Answer:

30.01 units

Step-by-step explanation:

Given vertices WXYZ:

W(-4,5), X(2,4), Y(3, -4), Z(-1, -6)

Perimeter is the sum of the side length.

Use distance formula to find each side:

WX = $\sqrt{(2+4)^2+(4-5)^2} =\sqrt{37}$ ≈ 6.08
XY = $\sqrt{(3-2)^2+(-4-4)^2} =\sqrt{65}$ ≈ 8.06
YZ = $\sqrt{(-1-3)^2+(-6+4)^2} =\sqrt{20}$ ≈ 4.47
WZ = $\sqrt{(-1+4)^2+(-6-5)^2} =\sqrt{130}$ $\sqrt{(-1+4)^2+(-6-5)^2}=\sqrt{130}$ ≈ 11.40