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3 years ago

Please help this is urgent!

Mathematics

2 answers:

Diano4ka-milaya [45]3 years ago

4 0

Answer:

Isosceles

Obtuse

Step-by-step explanation:

1) When two sides of a triangle are the same length, the triangle is an isosceles triangle.

2) When one angle of the triangle is greater than 90 degrees, the triangle is an obtuse triangle.

I hope this helps! Have a great day!

Elanso [62]3 years ago

4 0

Answer:

Isosceles, obtuse

Step-by-step explanation:

There are three types of triangles based on their sides:

Equilateral: a triangle with 3 equal sides
Isosceles: a triangle with 2 equal sides
Scalene: a triangle with no equal sides

This triangle here as sides of 28 cm, 16 cm, and 16 cm

This triangle has two equal sides of 16 cm, indicating it is an isosceles triangle

There are three types of triangles based on their angles:

Acute: when all angles are less than 90°
Right: when the triangle has one angle that is 90°
Obtuse: when one of the angles is greater than 90°

This triangle has angles of 26°, 26°, and 128°

This triangle has one angle that is greater than 90° → 128°, indicating that this is an obtuse triangle

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Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

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To determine the number of sequence, we need to understand how the sequence are generated

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$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$