Answer:
755,160 ways
Explanation:
We're told that 31 cars are in a race.
Considering the order in which the cars can finish in the top 4 positions, any of the 31 cars can finish in the first position, any of the remaining 30 cars can finish in the second position, any of the remaining 29 cars can finish in the third position and any of the remaining 28 cars can finish in the fourth position, so the different numbers of ways can be determined as seen below;
8-4k=40
-4k=32
k=-8 is the answer
You have to consider the sample space. In this example the sample space
is {1,2,3,4,5,6}
A simple event can be defined as a SINGLE outcome : Example getting a 3 OR 5 OR any other number from the sample space.
Now if you roll 1 dice & you want to get an even number (2,4,6) then you have chosen from the sample space 3 outcome & this is a compound event
Equally if you roll 2 dice and want to get "one" and/or "three" this is a compound event since you have chosen 2 outcome from the sample space.
Mind you, if you want 5 And 5 when rolling two dice it's a simple event because you have chosen ONE outcome from the sample space.
Hope this will help you to understand this kind of problem
You could use 10, 6 and 7.
Using ten would have them all equal 50, using 6 would have them all equal 30 and using 7 would have them all equal 35.
Hope this helps!
Answer:
101, 135, 131, 99, 138, 136, 140