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cestrela7 [59]
3 years ago
12

Which of these triangles appear not to be congruent to any others shown here ? Check all that apply.

Mathematics
2 answers:
mihalych1998 [28]3 years ago
5 0

Answer:

it b and d APEX

Step-by-step explanation:

Ymorist [56]3 years ago
4 0
The answer is B.
*Hope this helps!*
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FIRST -CORRECT- ANSWER WILL GET BRAINLIEST!!
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u=2 root 2

Step-by-step explanation:

All 45 45 90 degree triangles follow the same pattern

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Identify the numbers that are located below -3.5 on a vertical number line.
Mumz [18]
The answers are: -5.3, -6.5
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-x + y = 4<br>x + 3y =4​
Ymorist [56]
The answer is -2,2 for this problem
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15 and 3/5 as a fraction in simplest form
lianna [129]

Answer:

78/5

Step-by-step explanation:

(15 x 5 + 3)/5

78/5

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3 years ago
A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi
SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

= \frac{20!}{(20-5)! 5!)}

= \frac{20*19*18*17*16}{5*4*3*2*1}

= 15504

b) probabilities of A2, A5, A4

P(A2) = ⁵C₂ / ²⁰C₂

= \frac{20}{320} = \frac{1}{19}

P(A5) = ⁸C₅ / ²⁰C₅

= \frac{56}{15540} = \frac{7}{1938}

P(A4) = ⁷C₄ / ²⁰C₄

= \frac{35}{4845} = \frac{7}{969}

c) No,the events A2, A5, A4, do not comstitute a partition of the sample space. i.e P(A2)+P(A5)+P(A4) ≠ 1

5 0
3 years ago
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