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Answer:
3.90% probability that the third failure will occur on the tenth component tested
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not fail. Components perform independently. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Assume that a component passes a test is 0.85
So they fail with probability of
What is the probability that the third failure will occur on the tenth component tested
First 9 components: Two failures, that is, P(X = 2) when n = 9.
10th component: Failure with probability 0.15.
So
In which
So
3.90% probability that the third failure will occur on the tenth component tested
Answer:
7,200
Step-by-step explanation:
Let's start by calculating how many students the university accepts. The problem says they accept 60% of the students. 60% as a decimal is 0.6. To calculate 60% of something, you multiply .60 by whatever quantity. In this case, it would be the students.
Number of accepted students = = 18,000
The university accepts 18,000 students.
Now, the next problem is that of those accepted students, we need to find out how many actually enroll. The problem says they accept 40% of the accepted students. Applying the same principle,
Number of enrolled students = = 7,200
The number of students that actually enroll is 7,200.
Alternatively, would give you the same result.
Combining the pieces together, we are asking for 60% of 30,000. Then getting 40% of that 60%.