A = lw + 0.5bh
0.5bh = A - lw
b = (A - lw)/0.5h
option B is the correct option.
The answer is shown below:
Rectangle JKLM has an area of 36 square centimeters. The side is at least 4 centimeters long. Prove: KL is 9 centimeters. Assume that a. "KL > 0". Then the area of rectangle JKLM is greater than b.) "40 centimeters² ", which contradicts the given information that c. the area is 40 centimeters². So the assumption must be false. Therefore, d.) "KL <= 10".
Answer:
x = 4
Step-by-step explanation:
Since the terms are in an arithmetic progression then there is a common difference between consecutive terms, that is
2x - 1 - (x + 1) = x + 5 - (2x - 1) ← distribute parenthesis on both sides
2x - 1 - x - 1 = x + 5 - 2x + 1, that is
x - 2 = - x + 6 ( add x to both sides )
2x - 2 = 6 ( add 2 to both sides )
2x = 8 ( divide both sides by 2 )
x = 4
The 3 terms are 5, 7, 9
1. Multiply 5 by 2 since the piece is twice as long. That is 10.
Multiply 4 by 3 since the piece is 3 times as long. That is 12.
Her piece is 10 x 12.
2 sides of 10 & 2 sides of 12.
Multiply 10 & 12 by 2 to get 20 and 24. Add them together to get 44 inches, which is the perimeter.
2. Multiply 4 x 2 since length is twice width. That is 8.
Multiply 8 x 4 to get the area of the red paper. That is 32.
Multiply 3 x 7 to get the area of the blue paper. That is 21.
Subtract 21 from 32 to get the amount of red paper that wasn't covered up.
11 square cm were not covered up.
Hope this helps!
Answer:
81
Step-by-step explanation:
