The equation of a line in slope-intercept form through the point (3, -4) and had a slope of 6

Mathematics

1 answer:

Ket [755]3 years ago

4 0

Answer:

The equation of a line in slope-intercept form through the point (3, -4) and had a slope of 6 will be:

y = 6x - 22

Step-by-step explanation:

Given

The point = (3, -4)

Slope = m = 6

We know that the slope-intercept form of the line equation

y = mx+b

where

m is the slope

b is the y-intercept

substituting m = 6 and the point (3, -4) in the slope-intercept form of the line equation to determine the y-intercept b

y = mx+b

-4 = 6(3) + b

-4 = 18 + b

switch sides

b = -4 - 18

b = -22

now substituting m = 6 and the b = -22 in the slope-intercept form of the line equation

y = mx+b

y = 6x + (-22)

y = 6x - 22

Therefore, the equation of a line in slope-intercept form through the point (3, -4) and had a slope of 6 will be:

y = 6x - 22

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