Question

The equation of a line in slope-intercept form through the point (3, -4) and had a slope of 6

Answer 1

Answer:

The equation of a line in slope-intercept form through the point (3, -4) and had a slope of 6 will be:

• y = 6x - 22

Step-by-step explanation:

Given

• The point = (3, -4)

• Slope = m = 6

We know that the slope-intercept form of the line equation

y = mx+b

where

• m is the slope

• b is the y-intercept

substituting m = 6 and the point (3, -4) in the slope-intercept form of the line equation  to determine the y-intercept b

y = mx+b

-4 = 6(3) + b

-4 = 18 + b

switch sides

b = -4 - 18

b = -22

now substituting m = 6 and the b = -22 in the slope-intercept form of the line equation

y = mx+b

y = 6x + (-22)

y = 6x - 22

Therefore, the equation of a line in slope-intercept form through the point (3, -4) and had a slope of 6 will be:

• y = 6x - 22