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3 years ago

For the complex number 10+12i identify the real part and the imaginary part

1 answer:

7 0

Complex number = a +bi

a is a real part, bi - an imaginary part

So, in <span>10+12i
10 is a real part, 12i is an imaginary part.</span>

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Select all the groups the number pi belongs to:

amm1812

0.33 is rational 12 = Whole , real , irrational

4 0

3 years ago

4(x-11)^2=25

netineya [11]

Expand the square: 4(x-11)^ =25
4(x-11)(x-11)=25

Distribute : 4(x-11)(x-11)=25
4(x(x-11)-11(x-11))=25

Distribute: 4(x(x-11)-11(x-11))=25
4(x^-11x-11(x-11))=25

Solution: x=17/2
x=27/2

hope that helps

8 0

3 years ago

5m - 4n, when m=5 and n = 3.

tiny-mole [99]

Answer:

5m - 4n

5(5) - 4(3) ( As m= 5 and n= 3)

25 - 12

= 13

8 0

3 years ago

Read 2 more answers

Solve for x and y matrix

charle [14.2K]

Answer:

$x=-1$

$y=5$

Step-by-step explanation:

$\begin{pmatrix}x&y\\ \:-1&4\end{pmatrix}\begin{pmatrix}2&5\\ \:4&1\end{pmatrix}=\begin{pmatrix}18&0\\ \:14&-1\end{pmatrix}$

$\begin{pmatrix}x&y\\ -1&4\end{pmatrix}\begin{pmatrix}2&5\\ 4&1\end{pmatrix}$

$=\begin{pmatrix}x\times \:2+y\times \:4&5x+y\\ 14&-1\end{pmatrix}$

$=\begin{pmatrix}18&0\\ 14&-1\end{pmatrix}$

$\begin{bmatrix}x\times \:2+y\times \:4=18\\ 5x+y=0\end{bmatrix}$

$x=-1$

$y=5$

<u>OAmalOHopeO</u>

8 0

3 years ago

Use the Law of Cosines to find the missing angle. In triangle JKL, j=3in., k=4in., and l=2.89., find mJ

slega [8]

Using the law of cosine for Triangle KJL, we can write:

$j^{2} = k^{2} + l^{2}-2(k)(l)cos(J) \\ \\ 
2(k)(l)cos(J)=k^{2} + l^{2}- j^{2} \\ \\ 
cos(J)= \frac{k^{2} + l^{2}- j^{2}}{2(k)(l)}$

Using the values of k,j and l, we can write:

$cos(J)= \frac{ 4^{2} + (2.89)^{2} - 3^{2} }{2(4)(2.89)} \\ \\ 
cos(J)= 0.664 \\ \\ 
J= cos^{-1}(0.664) \\ \\ 
J=48.39$

Rounding to nearest integer, the measure of angle J will be 48 degrees.
So option B gives the correct answer

8 0

3 years ago

Read 2 more answers