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LenaWriter [7]
3 years ago
13

Multiply & simplify: (3x + 4)(x + 1)

Mathematics
2 answers:
UkoKoshka [18]3 years ago
4 0
4x-2 is this simplified
svetoff [14.1K]3 years ago
3 0
You would distribute which would give you
3x^2+3x+4x+4
And then you would simplify
3x^2+7x+4
The answer is: 3x^2+7x+4
(^2 means squared)
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A plane intersects one nappe of a double-napped cone such that it is perpendicular to the vertical axis of the cone and it does
Colt1911 [192]
There is two possible conic section that can be formed when the plane intersects the vertical axis, a circle, and an ellipse. Cutting one nappe of double napped cone perpendicular to the vertical axis means the cut is straight across the cone making a right angle. The conic section formed would be a circle. 
7 0
3 years ago
Read 2 more answers
Solve using substitution.<br> y = -2<br> -7x - y = -5
Natasha_Volkova [10]

Step-by-step explanation:

- 7x - ( - 2) =  - 5 \\  - 7x + 2 =  - 5 \\  - 7x =  - 7 \\ x = 1 \\

5 0
3 years ago
A landscaper has enough cement to make a patio with an area of 150 Sq ft. The homeowner wants the length of the patio to be 6 ft
Natasha_Volkova [10]
A=lw=150\\l=w+6\\(w+6)w=150\\w^2+6w=150\\w^2+6w-150=0\\w=\frac{-b+-\sqrt{b^2-4ac}}{2a}\\w=\frac{-(6)+-\sqrt{(6)^2-4(1)(-150)}}{2(1)}\\w=\frac{-6+-\sqrt{36+600}}{2}\\w=\frac{-6+-\sqrt{636}}{2}\\w=\frac{-6+-2\sqrt{159}}{2}\\w=-3+-\sqrt{159}>0\\w=-3+\sqrt{159}\\\\l=(-3+\sqrt{159})+6\\l=3+\sqrt{159}

Width = -3 + sqrt(159)
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4 0
3 years ago
-4.25 ⋅ (3/10 + 1/5)
elixir [45]

Answer: -0.85

Step-by-step explanation:

3/10 + 1/5 = 1/2

1/2 x -4.25 = -0.85

3 0
1 year ago
Make a table for the following equations<br> y = 2x + 4
nekit [7.7K]

In order to make a table, we sample some x values (whichever we want), and we compute the expression for those value. Each x value will yield a unique y value.

If you need this table to graph the function, you'll only need two points, since this is a line, and having two points you just need to connect them.

Here are some samples, feel free to make more if you need to:

f(x)=2x+4\implies f(0)=2\cdot 0 + 4 = 4

f(x)=2x+4\implies f(1)=2\cdot 1 + 4 = 6

f(x)=2x+4\implies f(2)=2\cdot 2 + 4 = 8

f(x)=2x+4\implies f(3)=2\cdot 3 + 4 = 10

f(x)=2x+4\implies f(4)=2\cdot 4 + 4 = 12

So, we have the following table

\begin{array}{c|c}0&4\\1&6\\2&8\\3&10\\4&12\end{array}

4 0
3 years ago
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