Question

What do these three steps result in the formation of?In the presence of oxygen, the three-carbon compound pyruvate can be catabolized in the citric acid cycle. First, however, the pyruvate 1. loses a carbon, which is given off as a molecule of CO2, 2. is oxidized to form a two-carbon compound called acetate, and 3. is bonded to coenzyme A.
A. Acetyl CoA, O2, and ATP.B. Acetyl CoA, FADH2, and CO2.C. Acetyl CoA, FAD, H2, and CO2.D. Acetyl CoA, NADH, H+, and CO2.E. Acetyl CoA, NAD+, ATP, and CO2.

Answer 1

Answer:acetyl CoA, NADH, H+, and CO2

Explanation:

In The formation ,

the pyruvate molecules depends on whether oxygen is present.

If oxygen isn't available, the pyruvate is converted to lactate, and no additional ATP is produced from this conversion

Answer 2

Answer:

the correct option is D.  i.e ACETYL CoA , NADH, H+ and CO2.

Explanation:

Pyruvic acid or PYRUVATE is the end product of Glycolysis and before entering citric acid cycle it is oxidized.In the second step ,where it is oxidized to 2-carbon compound i.e ACETATE ,one carbon is released as CO2 (decarboxylation). This acetate ,on entering the mitochondrion binds with coenzyme A to form ACETYL CoA .and the NAD+ converts into NADH and more H+. thus the oxidation of pyruvate yields ACETYL CoA,NADH,H+ and CO2.