Answer:
36x² - 9y²
Step-by-step explanation:
We see that the given expression (6x + 3y)(6x - 3y) looks just like the expression (a + b)(a - b). When multiplied out, this is a difference of squares identity that I highly recommend you memorise:
(a + b)(a - b) = a² - b²
Here, a = 6x and b = 3y, so plug these in:
(6x + 3y)(6x - 3y) = (6x)² - (3y)² = 36x² - 9y²
<h2>Given</h2>
- A quadrilateral ABCD with opposite pairs of sides being congruent.
<h2>To prove</h2>
- Opposite sides are parallel.
<h2>Solution</h2>
We'll prove first the triangles formed by diagonal are congruent then we'll prove the angles on either side of diagonal are congruent.
<u>The steps are:</u>
- Step ⇒ Statement ⇒ Reason
=============================================================
- 1 ⇒ AB ≅ CD and BC ≅ AD ⇒ Given
- 2 ⇒ AC = CA ⇒ Common side
- 3 ⇒ ΔABC ≅ ΔCDA ⇒ Side-side-side congruence
- 4 ⇒ ∠BAC ≅ ∠DCA ⇒ Corresponding angles of congruent triangles
- 5 ⇒ ∠BAC and ∠DCA are alternate interior angles ⇒ Definition of alternate interior angles
- 6 ⇒ AB║CD ⇒ The converse of alternate interior angles theorem
- 7 ⇒ ∠BCA ≅ ∠DAC ⇒ Corresponding angles of congruent triangles
- 8 ⇒ ∠BCA & ∠DAC are alternate interior angles ⇒ Definition of alternate interior angles
- 9 ⇒ BC║AD ⇒ The converse of alternate interior angles theorem
Idk but maybe key words maybe it’s D don’t quote me tho
Based off of what I can see in the photo (its too blurry to know for sure) and what I think you're asking:
The angle of a triangle always adds up to 360degrees, so base it on that and the acute and obtuse angles and get the degrees from there, the angle would be those degrees you find or <10, 5, 4 (what I assume is a 5)
