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docker41 [41]
2 years ago
13

Given: AB is congruent to CD and BC is congruent to AD Prove: AB ll CD and BC ll AD

Mathematics
1 answer:
kifflom [539]2 years ago
4 0
<h2>Given</h2>

  • A quadrilateral ABCD with opposite pairs of sides being congruent.

<h2>To prove</h2>

  • Opposite sides are parallel.

<h2>Solution</h2>

We'll prove first the triangles formed by diagonal are congruent then we'll prove the angles on either side of diagonal are congruent.

<u>The steps are:</u>

  • Step  ⇒   Statement  ⇒   Reason

=============================================================

  • 1   ⇒  AB ≅ CD and BC ≅ AD     ⇒     Given
  • 2  ⇒  AC = CA                              ⇒    Common side
  • 3  ⇒  ΔABC ≅ ΔCDA                   ⇒    Side-side-side congruence
  • 4  ⇒  ∠BAC ≅ ∠DCA                   ⇒    Corresponding angles of congruent triangles
  • 5  ⇒  ∠BAC and ∠DCA are alternate interior angles  ⇒  Definition of alternate interior angles
  • 6  ⇒  AB║CD                               ⇒   The converse of alternate interior angles theorem
  • 7  ⇒  ∠BCA ≅ ∠DAC                   ⇒   Corresponding angles of congruent triangles
  • 8  ⇒  ∠BCA & ∠DAC are alternate interior angles  ⇒  Definition of alternate interior angles
  • 9  ⇒ BC║AD                                ⇒   The converse of alternate interior angles theorem
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olga55 [171]

Answer: 67°.

Step-by-step explanation:

1) m∠PMR=m∠LMN=3x+19°;

2) m∠LMN+m∠LMP=180°, it can be written as 3x+19+9x-31=180;

3) if to solve the equation 3x+19+9x-31=180, then x=16;

4) m∠PMR=3x+19=48+19=67°.

3 0
2 years ago
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Can somebody help plz​
Evgen [1.6K]

Answer:

(3,2)

Step-by-step explanation:

the other three ordered pairs do not lie in the shaded region

6 0
3 years ago
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(08.01 LC)
Mrac [35]

Answer:

this answer requires that you do a little solving to find all the dimensions we need for the volume.

We know that H (height) = 2m

Diameter = 5 x height, so

Diameter = 5 x 2m = 10m

If you have the formula for finding the volume of a cylinder, it is basically the area of the circular base x cylinder height. You may know already that the area of a circle is (pi) x radius2

So this will be 2 (the height) x (pi) x r2

As we just figured out, the DIAMETER is 10, so the radius is half the diameter = 5.

This brings our volume to 2 x (pi) x 52

= 2 x (pi) x 25

2x25 = 50, so we have 50 x (pi).

Pi = 3.14

50 x 3.14 = 157

And don't forget your units = 157 m3

8 0
3 years ago
Cindy has two bags
Bumek [7]

Answer:

Step-by-step explanation:

There are a total of 10 balls in the first bag, so P(1 red) = 3/10 and P(1 green) = 7/10.There are a total of 9 balls in the second bag, so P(2 red) = 4/9 and P(2 green) = 5/9.P(1 red & 2 red) = 3/10 × 4/9 = 12/90 = 2/15P(1 red & 2 green) = 3/10 × 5/9 = 15/90 = 1/6P(1 green & 2 red) = 7/10 × 4/9 = 28/90 = 14/45P(1 green & 2 green) = 7/10 × 5/9 = 35/90 = 7/18

I hope you understand it!

7 0
3 years ago
Look at the rectangle and the square: Ada says that the length of diagonal SQ is two times the length of diagonal OM. Is Ada cor
Musya8 [376]

Answer:

No, she is wrong.

Step-by-step explanation:

A diagonal of square or rectangle is equals to hypotenuse of a triangle. So you can apply Pythagoras Theorem to solve it :

{c}^{2}  =  {a}^{2}  +  {b}^{2}

Rectangle,

{qs}^{2}  =  {rs}^{2}  +  {qr}^{2}

{qs}^{2}  =  {16}^{2}  +  {8}^{2}  = 320

qs =  \sqrt{320}  = 17.9 \: inches

Square,

{om}^{2}  =  {lo}^{2}  +  {lm}^{2}

{om}^{2}  =  {8}^{2}  +  {8}^{2}  = 128

om =  \sqrt{128}  = 11.3 \: inches

Given that QS is 17.9 and OM is 11.3. So SQ is not 2 times greater than OM.

17.9 \div 11.3 = 1.58 \: (not \: equals \: to \: 2)

7 0
3 years ago
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