Question

1.) Given P(E or F) = 0.82, P(E) = 0.18, and P(E and F) = 0.09, what is P(F)?

Answer 1

Answer:

p(F)=0.73

Step-by-step explanation:

we have by identity

$p(A\cup B)=p(A)+p(B)-p(A\cap B)$

Thus for given events E and F

we have$p(E\cup F)=p(E)+p(F)-p(E\cap F)$

Applying values we get

$p(F)=p(E\cup F)+p(E\cap F)-p(E)$

Thus

p(F) = 0.82+0.09-0.18

p(F) = 0.73