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k0ka [10]
3 years ago
8

C and d please help me im stuck i promise i will give a thank

Mathematics
1 answer:
Troyanec [42]3 years ago
3 0

Answer:

attach the graph in orfer for us to answer

Step-by-step explanation:

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Please answer all with explanation
stepladder [879]

3b.4+y/3=2

12+y/3=2

12+y=6

y=6-12

y=-6

.

8 0
2 years ago
The expression 100 + 20m, gives the volume of water in Eduardo’s pool (in liters) after Eduardo spends m minutes filling his poo
Alex17521 [72]

205 liters in 5 1/4 minutes

m = 5 1/4

20 (5 1/4) = 105

100+105= 205

3 0
2 years ago
Brad buys two packages of mushrooms. He paid $11.25 for 2/3 lb of Cremini mushrooms and $7.99 for 1/2 lb of Chanterelle mushroom
vlabodo [156]

Answer:

C. (Chanterelle mushrooms cost less by $0.90)

Step-by-step explanation:

Divide 11.25 by 2/3, for the total amount of pound for the Cremini.

Do the same thing for Chanterelle, but the numbers given for it.

We than find out that Cremini=16.87, and Chanterelle=15.98

Now that we know Cremini is more that Chanterelle, we need to find the difference, by subtracting The bigger number by the smaller number.

Our answer is 0.89, but we will round it to 0.90.

Now we know that the Cremini costs more by $0.90, and the Chanterelle costs less by $0.90

5 0
3 years ago
Read 2 more answers
I need help on this please
Leya [2.2K]

The expression we have is:

2xy\cdot xy^2

And we are given some values for x and y:

\begin{gathered} x=2 \\ y=4 \end{gathered}

The first step will be to substitute the given values into the expression:

2(2)(4)\cdot(2)(4)^2

The next step is to solve 4^2 which is equal to 16:

2(2)(4)\cdot(2)(16)

And then we solve the multiplications, 2(2)(4) is equal to 16 and (2)(16) is equal to 32:

16\cdot32

Solving this final multiplication we get the result:

512

Answer: 512

8 0
1 year ago
Part C: Of the following choices, which equation is the best fit line for the data
KatRina [158]

Step-by-step explanation:

Part C: Of the following choices, which equation is the best fit line for the data

As we can see from the data, the population size are decreased year by year, so the slope of the line of best fit must be a negative number.

So we have: C and D left.

Let x = 0, year 2005, the population size is 296 around 320, hence, we choose D.

D f(x) = -34x + 320

Part D: What is the predicted population size for the year 2010? How does that compare to the real data? Round to the nearest million.

year 2010, x =5 so let substitute x =5 into  f(x) = -34x + 320

<=> f(x) = -34*5 + 320

= 150 mil

The result is smaller than the real data, (201-150 = 51 mil)

Part E: In what year is the population predicted to go extinct

the population predicted to go extinct when f(x)= 0

<=> -34x + 320 = 0

<=> x  ≈ 9.4

So after 10 years, the the population predicted to go extinct

3 0
3 years ago
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