The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is

a1=1
r=2
we want to find

(since we minus 1, the highest exponet is 9 so add 1 to make it correct)



Answer:
Simplified= −x+9
Step-by-step explanation:
12a−a
=12a−1a
=12a+−1a
=a+a+a+a+a+a+a+a+a+a+a+a+−a
=a+a+a+a+a+a+a+a+a+a+a
=11a
Check the picture below.
make sure your calculator is in Degree mode.