There are 2 angle measurements not identified.
Angle ACB and angle ABC.
To find angle ACB you need to know that a straight line is 180 degrees, so if the angle to the right is 131, the angle to the left (Angle ACB) must be 49 degrees.
To find angle ABC, you need to know that the sum of all 3 angles in a triangle equal 180 degrees, so 180 - (49 + 44) = 87 degrees. Angle ABC is 87 degrees.
Solve for x:
10 (x + 2) = 5 (x + 8)
Expand out terms of the left hand side:
10 x + 20 = 5 (x + 8)
Expand out terms of the right hand side:
10 x + 20 = 5 x + 40
Subtract 5 x from both sides:
(10 x - 5 x) + 20 = (5 x - 5 x) + 40
10 x - 5 x = 5 x:
5 x + 20 = (5 x - 5 x) + 40
5 x - 5 x = 0:
5 x + 20 = 40
Subtract 20 from both sides:
5 x + (20 - 20) = 40 - 20
20 - 20 = 0:
5 x = 40 - 20
40 - 20 = 20:
5 x = 20
Divide both sides of 5 x = 20 by 5:
(5 x)/5 = 20/5
5/5 = 1:
x = 20/5
The gcd of 20 and 5 is 5, so 20/5 = (5×4)/(5×1) = 5/5×4 = 4:
Answer: x = 4
Three fractions equivalent to ⅔ are 4/6 , 8/12, and 16/24
Three fractions equivalent to ¾ are 6/8, 12/16, and 24/32
Three fractions equivalent to 4/5 are 8/10, 16/20 and 32/40
Substitute
in the first equation with
from the other equation.
Then you have
Answer:
s=3
Step-by-step explanation:
27=9•s
Divide each side by 9
27/9 = 9s/9
3 =s