How to do multiplication solve and check

Mathematics

1 answer:

Lunna [17]3 years ago

5 0

This is how you do it !!!

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Natalie is ordering a burrito. For the main protein, she is given the option of veggie, chicken, carnitas, or carne asada. For t

muminat

Answer: 12

Step-by-step explanation:

For this counting question, we need to figure out the possible choices for each selection.

For main protein, there are four options, so we can make four slots

_ _ _ _

For beans, there's three options, so we can make three slots
_ _ _

Doing some casework, we know that 4*3 = 12, which is the answer.

3 0

2 years ago

Sin ^6x-cos^6÷1-sin^2x*cos^2x=1-2cos^2x<br><br>

lilavasa [31]

Answer:

$\frac{\sin^{6} x-\cos^{6}x }{1-\sin^{2}x \cos^{2}x } =1-2\cos^{2} x$ proved.

Step-by-step explanation:

We have to prove that $\frac{\sin^{6} x-\cos^{6}x }{1-\sin^{2}x \cos^{2}x } =1-2\cos^{2} x$

So, the left hand side = $\frac{\sin^{6} x-\cos^{6}x }{1-\sin^{2}x \cos^{2}x }$

= $\frac{(\sin^{2}x-\cos^{2} x )(\sin^{4} x+\cos^{4}x+\sin^{2}x \cos^{2}x) }{{1-\sin^{2}x \cos^{2}x }}$ {Since we have the formula $a^{3} -b^{3}= (a-b) (a^{2} +ab+b^{2} )$ }

= $\frac{(\sin^{2}x-\cos^{2} x )[(\sin^{2}x+\cos^{2}x )^{2}-2\sin^{2}x\cos^{2} x+ \sin^{2}x\cos^{2} x ]}{{1-\sin^{2}x \cos^{2}x }}$ {Since we have the formula $a^{2}+b^{2} = (a+b)^{2} -2ab$ }