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FromTheMoon [43]
3 years ago
7

Help me please I need to answer this

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
8 0
The answer is A.

If you multiply both fractions by 10 minutes, you can find that A ran 1 mile in 10 minutes and T ran half a mile in 10 minutes. This is true because the graph shows it.
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Jared can run 520 yards in one minute. how fast does he run in feet per second answer key
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<span>Jared can run 520 yards in one minute and you are asked to change the unit to feet/second. One yard will be equal to 3 feet. One minute equal to 60 seconds. Then, the speed would be:
(520 yards/minute )* (3 feet/yard) / (60 second/minute)= 26 feet/second</span>
5 0
3 years ago
Please hurry algebra 2
Lelu [443]

Answer:

the answer should be the second option idk for sure sorry if wrong.

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Manufacturers don’t like defective products because it can give their brands a bad reputation. However, no production line is pe
Elena-2011 [213]

Answer:

0.99804932311

Step-by-step explanation:

We solve this using binomial probability

Binomial probability formula

= nCx × p^x × q^n - x

= n!/(n - x)! x!

Where n = Number of trials = 25 samples

x = Number of successes = 23

p = probability of success = 99% = 0.99

q = probability of failure = 1 - p

= 1 - 0.99

= 0.01

Hence,

p(at least 23 are properly filled) = p(X ≥ x)

= [25!/(25 - 23)! × 23! × 0.99^23 × 0.01^25 - 23 ]+ [25!/(25 - 24)! × 24! × 0.99^24 × 0.01^25 - 24 ]+ [25!/(25 - 25)! × 23! × 0.99^25 × 0.01^25 - 25]

= [300 × 0.99 ^23 × 0.01^2] + [25 × 0.99^24 × 0.01^1] + [1 × 0.99^25 + 0.01^0]

= 0.0238084285 + 0.1964195352 + 0.7778213594

= 0.99804932311

3 0
3 years ago
Can someone help me :(
Ivan
The triangles are similar by AAA so make ratios and solve
\frac{21}{14}  =  \frac{x}{20} \\ x =  \frac{21 \times 20}{14}  \\ x = 30
7 0
3 years ago
Review: Find the area of this irregular shape
sp2606 [1]

Answer:

33.5

Step-by-step explanation:

just separate this shape into triangles and rectangles and find the area of those shapes separately then add them altogether.

hope this helped (:

8 0
3 years ago
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