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AnnyKZ [126]
4 years ago
14

Which explanation correctly solves this problem?

Mathematics
2 answers:
Keith_Richards [23]4 years ago
8 0

I believe it is C :) please tell me if i am wrong UvU                          

sveta [45]4 years ago
4 0
Given:
Left over fence: 13.5 feet
Used during the day:
2.5 ft - 1 pc
6.75 ft - 2 pcs
12 ft - 1 pc

Length of fence at the beginning of the day.

2.5ft(1) + 6.75ft(2) + 12ft(1) + 13.5ft(1) 
2.5 ft + 13.5 ft + 12ft + 13.5ft = 41.5 ft 

C.
<span>Start with 13.5. Add 2.5 to it. Multiply 6.75 by 2 and add the sum and the product together. Then add 12 to the answer.</span>

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How do I determine the 50th term for the sequence <br> -5, -1, 3, 7, 11
Mademuasel [1]
The sequence is going up by 4 so u have to multiply each term by four and the -5 is it’s 0th term as well it’s beginning so you have to input that in the equation as well
4(50) - 5 = 200 - 5 = 195
I’m not very good at explaining so I hope u get it
5 0
4 years ago
Some friends of yours collected books for a book drive. They collected 64 Fiction, and 48 Non-Fiction books. They asked you to m
Cloud [144]

As all of the bundles have the same content inside, so assuming that there is x number of Fiction books and y number of Non-fiction books in each bundle.

Let n be the total number of bundles that my team can send.

There are 64 Fiction books, so

nx=64 ...(i)

Or x=64/n ...(ii)

also, there are 48 Non-Fiction books, so

ny=48 ...(iii)

Or y=48/n ...(iv)

Observing that the numbers x, y, and n are counting numbers and from equations (i) and (iii), n is the common factor of 64 and 48.

The possible common factors of 64 and 48 are,

n=1,2,4,8, and 16.

So, my team can send 1,2,3,4,8 or 16 bundles of books.

Now, from equations (ii) and (iv),

For n=1:

x=64/1=64

y=48/1=48

So, for 1 bundle the number of Fiction and Non-fictions books are 64 and 48 respectively.

For n=2:

x=64/2=32

y=48/2=48

So, for 2 bundles, the number of Fiction and Non-fictions books are 32 and 24 respectively.

For n=4:

x=64/4=16

y=48/4=12

So, for 4 bundles, the number of Fiction and Non-fictions books are 16 and 12 respectively.

For n=8:

x=64/8=8

y=48/8=6

So, for 8 bundles, the number of Fiction and Non-fictions books are 8 and 6 respectively.

For n=16:

x=64/16=4

y=48/16=3

So, for 16 bundles, the number of Fiction and Non-fictions books are 4 and 3 respectively.

8 0
4 years ago
Which radical expression in the picture is equivalent to t^5/8?
mixas84 [53]
<h3>Answer: Choice B</h3>

=========================================================

Explanation:

The rule we use is

\Large a^{m/n} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m

where 'a' is the base, m stays in the role of the exponent, and n plays the role of the root index (eg: n = 3 is a cube root, n = 4 is a fourth root, and so on).

So for instance,

\Large 2^{3/4} = \sqrt[4]{2^3} = \left(\sqrt[4]{2}\right)^3

or in this case,

\Large t^{5/8} = \sqrt[8]{t^5} = \left(\sqrt[8]{t}\right)^5

5 0
3 years ago
26. Find (g-|(2). Use f(x) = 2x – 1 and g(x) = x + 5.<br> a. 4<br> b. 2<br> c. 4.<br> d. 6
schepotkina [342]

Answer:

4dyhdhdjdjjddhjdjdhdudhf

5 0
3 years ago
Which angles are coterminal with an angle drawn in standard position measuring 282°?
vampirchik [111]

Answer:

−438°, -78°, 642°

Step-by-step explanation:

Given angle:

282°

To find the co-terminal angles of the given angle.

Solution:

Co-terminal angles are all those angles having same initial sides as well as terminal sides.

To find the positive co-terminal of an angle between 360°-720° we will add the angle to 360°

So, we have: 282\°+360\°=642\°

To find the negative co-terminal of an angle between 0° to -360° we add it to -360°

So, we have:  282\°-360\°=-78\°

To find the negative co-terminal of an angle between -360° to -720° we add it to -720°

So, we have:   282\°-720\°=-438\°

Thus, the co-terminal angles for  282° are:

−438°, -78°, 642°

7 0
3 years ago
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