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FrozenT [24]
3 years ago
13

Which of the following is a solution to 2cos x + 1 = 0? 60° 120° 210° 300°

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
7 0

Answer:

correct answer is second option (The solution of 2cos x + 1 = 0 is x=120^o)

Step-by-step explanation:

In this question we have given

2cos x + 1 = 0

2 cos x = -1

therefore,

cos x = -\frac{1}{2}

x =cos^{-1}( -\frac{1}{2})

therefore,

x=120^o

because cos(120)=-\frac{1}{2}

Therefore,

The solution of 2cos x + 1 = 0 is x=120^o

klasskru [66]3 years ago
6 0
Rewrite   <span>2cos x + 1 = 0    as:

2 cos x = -1, and then cos x = -1/2

x must be in Quadrant II or Quadrant III, since the adj. side is negative.

Note that the angle 120 has adj. side -1 and hyp 2.  So 120 degrees is one solution.  

Now what about a possible 2nd solution, to be found in Quadrant III?  That would be -120 degrees, which has the same terminal line as does 240 degrees.

No soap.

So, the solution is 120 degrees.</span>
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What is (-7)^-1 and how do you do it
Zolol [24]

Answer:

-1/7

Step-by-step explanation:

First you need to understand negative exponents. Baisically it means 1/the number to the positive power. For this problem, it's

1/(-7)^1

-7^1=-7

(-7)^-1=-1/7

3 0
3 years ago
Read 2 more answers
Math! :( no links answer correct for brainliest!
dem82 [27]
90 squareroot 2
In decimal form it’s 127.27922
4 0
3 years ago
Sarah use three-quarters pound of blueberries to make a half a cup of jam how many pounds of blueberries would she need to make
Evgen [1.6K]
She wold need 1.5 pounds because you doubled the result, so you double th recipe, which means you multiply 3 quarters pound (.75 lbs) times 2, which equals 1.5 lbs. 
5 0
3 years ago
Who packed all the pies? Kane’s bakery makes four flavour pies. The weight of each flavour pie is follows:
svet-max [94.6K]
This is an identical problem answered by myself a few days ago.  The answer is reproduced below for your convenience.

It is a very difficult problem if the box sizes are smaller or if there are more pies to pack.
For this particular problem, we first calculate the total weight of pies:
4 apple pies at 700 g = 2800 g
8 banoffee pies at 725 g =5800 g
3 custaard pies at 600 g = 1800 g
5 rhubarb pies at 675 g = 3375 g
for a total of 13775 g

The minimum number of boxes needed will be 13775/4000=3.44, or at least 4 boxes will be required.

We also note that 4 boxes will hold 16000 g, and we only need to pack 13775g, so there is a lot of margin.

We can proceed to do the mechanical way, fill in order of apple, banoffee, custard, and finally rhubarb pies.Following table shows how we fill, naively:      box content               Remaining to pack
Box A B C R     Weight    A B C R   
0                                      4  8  3 5     (original order)
1     4  1  0 0     3525       0  7  3 5
2     0  5  0 0     3625       0  2  3 5
3     0  2  3 0     3250       0  0  0 5
4     0  0  0 5     3375       0  0  0 0
Total weight     13775 g

So that does the job, 4 boxes (minimum) with none exceeding 4000 g to pack a total of 13775 g of pies.
 
Brainly - brainly.com/sf/question/8898504
5 0
3 years ago
HELLPP DUE BY 1pm PACIFIC HELLPP ASAP
HACTEHA [7]

Answer:644.355

i tried ok

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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