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sukhopar [10]
3 years ago
14

Could someone please help!!

Mathematics
1 answer:
Nastasia [14]3 years ago
6 0
<span>The first two terms of a geometric sequence are a1=1/3 and a2=1/6. what is a8 the 8th term?
r=(1/6)/(1/3) = 1/2
a(8)= ar^7 = (1/3)(1/2)^7 = 1/3*1/128= 1/384</span>
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What is the difference when the sum of 15 and 10 is subtracted from the product of 15 and 10.
Eva8 [605]

Answer:

125

Step-by-step explanation:

15+10=25

15x10=150

150-25=125

6 0
3 years ago
Read 2 more answers
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
3 years ago
How is 0.09 smaller than 0.1
denis-greek [22]

Answer:

0.09 < 0.1

Step-by-step explanation:

Remember that it doesn't matter how many numbers are after the tenths place of a decimal point what matters is the tenths place itself. If you have a decimal that has dozens of numbers but it's tenth place is a 3 and then you have a decimal with 5 numbers in whole but it's tenths place is 4, the 4 is greater then the 3 simply because it's greater in tenths.

Hope this helps.

5 0
3 years ago
I need help on this please
galina1969 [7]

Answer: 2.5 then 100.5

Step-by-step explanation:

8 0
3 years ago
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Select the correct answer.
maw [93]

Answer:where are the options ???

Step-by-step explanation:

8 0
2 years ago
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