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3 years ago

When x = 8, y=20. Find y when x = 42.

1 answer:

6 0

X=8. x=42
y=20. y=?

First you find the dividend of 20 and 8:
20/8= 2.5

Then... u multiply the dividend with the x value to get a y value
( 42•2.5)

So y=105

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In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p

hichkok12 [17]

Answer:

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

4 0

3 years ago

How solve this <br> x+y=5<br> X-y=7

Misha Larkins [42]

$elimination\ methode\\\\\underline{+\left\{\begin{array}{ccc}x+y=5\\x-y=7\end{array}\right}\ \ \ \ |add\ both\ sides\ of\ the\ equations\\.\ \ \ \ \ \ 2x=12\ \ \ \ \ |divide\ both\ sides\ by\ 2\\.\ \ \ \ \ \ \ \boxed{x=6}\\\\subtitute\ the\ value\ of\ x\ to\ the\ first\ equation:\\\\6+y=5\ \ \ \ |subtract\ 6\ from\ both\ sides\\\boxed{y=-1}\\\\Answer:\boxed{\left\{\begin{array}{ccc}x=6\\y=-1\end{array}\right}$

6 0

3 years ago

HELP PLZZ<br><br> Which figure shows a reflection of pre-image DEFG over the x-axis?

scoray [572]

The first one is a reflection over the x-axis :)

5 0

3 years ago

suppose 25 out of 175 people said they like to play disc golf and out 5 out of every twelve of the players have a personalized b

Serhud [2]

We have $\frac{5}{12}$ of 252 people who have a personalized black disc

Number of people who would have personalized flying disc = $\frac{5}{12}*252= \frac{2*252}{12}=105$ people

Then we work out the number of people who like to play disc golf:
$\frac{25}{175}*105= \frac{25*105}{175}=15$ people

So we have 15 people who like to play disc golf and have personalised black disc.

8 0

3 years ago

(1 pt) Which answer best describes the solution to the equation 3m – 9 = 9 + 3m?

seropon [69]

3m-9=9+3m
add 9 to both sides
3m=18+3m
minus 3m both sides
0=18
false
no solution

the best discription would be an empty solution set

3 0

3 years ago