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grin007 [14]
3 years ago
9

A literature professor decides to give a 10-questiontrue-false quiz to determine who has read an as-signed novel. She wants to c

hoose the passing gradesuch that the probability of passing a student whoguesses on every question is less than .05. What score should she set as the lowest passing grade?

Mathematics
1 answer:
Darya [45]3 years ago
7 0

Answer:

The teacher should set the score 7 as the lowest passing grade.

Step-by-step explanation:

Let <em>X</em> = number of correct guesses.

All the questions are of true-false format.

The probability of getting a correct answer is, <em>p</em> = 0.50.

The total number of questions is, <em>n</em> = 10.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p </em>= 0.50.

The probability mass function of <em>X</em> is:

P(X=x)={10\chose x}0.50^{x}(1-0.50)^{10-x};\ x=0,1,2,3...

Now the teaches chose the grading scheme such that the probability of passing a student who guesses on every question is less than 0.05.

Then the probability of failing such a students is at least 1 - 0.05 = 0.95.

Compute the probability distribution of <em>X</em>.

Consider the probability distribution attached below.

The value of <em>x</em> for which P (X ≤ x) is at least 0.95 is, <em>x</em> = 7.

So the teacher should set the score 7 as the lowest passing grade.

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I will give brainliest for question! How many nonzero terms are in the expansion of (x+4)(2x^2+3x+9)-3(x^3-2x^2+7x)?
nataly862011 [7]

Answer:

Four

Step-by-step explanation:

Let's expand and see how many nonzero terms:

⇒ (x+4)(2x²+3x+9)-3(x³-2x²+7x)=

⇒ 2x³ + 3x² + 9x + 8x² + 12 + 36 - 3x³ + 6 x² - 21 x=

⇒ - x³ + 17x² - 12x + 12

As we see the expression has four nonzero terms

4 0
3 years ago
The data below represents the number of hours an office assistant spends on the phone every week for 15 weeks.
Veronika [31]

A box plot contains two dots placed at the ends of the data for the mininum and the maximum value with a line placed over the median.

Let's put the numbers in your set in order from low to high:

5

6

7

8

9

9

9

10

12

14

17

17

18

19

19

The median is the middle number. We have 15 numbers so we select the 8th number - 7 from each end. In this set, 10 is the median.

Only one box plot has dots at 5 and 19 and a median of 10 - choice B. Thus, B is the proper box plot.

3 0
3 years ago
Read 2 more answers
1.<br> What is the solution of the system of equations?<br> y = 3x - 4<br> -3y = -9x + 12
Misha Larkins [42]

Answer:

Step-by-step explanation:

-3(3x - 4) = -9x + 12

-9x + 12 = -9x + 12

0 = 0

infinitely many solutions

5 0
4 years ago
Multiply: 14.3 x 0.5
Ainat [17]

Answer:7.15

Step-by-step explanation: You multiply it

6 0
3 years ago
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About 33% of people who get their feet examined are found to have an ingrown toenail. What is the probability of a podiatrist ex
enot [183]

Answer:

The correct answer is 0.94147

Step-by-step explanation:

Let A denote the event that the podiatrist finds the first person with an ingrown toenail.

And (1 - A) denote the event that the podiatrist does not find the ingrown toenail.

While examining seven people, the podiatrist can find the very first person to have an ingrown toenail. Similarly he can find the second patient to have the ingrown toenail. Going in this way the probability of the first person to have an ingrown toenail is given by:

= A + (1 - A) × A + (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) ×  (1 - A) × (1 - A) × (1 - A) × (1 - A) × A.

= \frac{1}{3} + \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} .

= \frac{1}{3} + \frac{2}{3} \frac{1}{3} + (\frac{2}{3}) ^{2} \frac{1}{3} + (\frac{2}{3})^{3} \frac{1}{3} + (\frac{2}{3})^{4} \frac{1}{3} + (\frac{2}{3})^{5} \frac{1}{3} + (\frac{2}{3})^{6} \frac{1}{3}.

= 0.94147

We can also solve the above expression by using the geometric progression formula as well where common ratio is given by \dfrac{2}{3}.

8 0
3 years ago
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