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GalinKa [24]
3 years ago
13

96=-8k solve Show work

Mathematics
2 answers:
Lisa [10]3 years ago
6 0

Answer:Simplifying

96 = -8k

Solving

96 = -8k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '8k' to each side of the equation.

96 + 8k = -8k + 8k

Combine like terms: -8k + 8k = 0

96 + 8k = 0

Add '-96' to each side of the equation.

96 + -96 + 8k = 0 + -96

Combine like terms: 96 + -96 = 0

0 + 8k = 0 + -96

8k = 0 + -96

Combine like terms: 0 + -96 = -96

8k = -96

Divide each side by '8'.

k = -12

Simplifying

k = -12

Step-by-step explanation:

larisa86 [58]3 years ago
3 0

Answer:

k = -12

Step-by-step explanation:

<u>Step 1:  Divide both sides by -8</u>

<u />96 / -8 = -8k / -8

-12 = k

Answer: k = -12

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Alma ask money to buy a bicycle of $150. his mom give him $40 at the moment and gives kyle $10 each month to pay the total of th
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Answer: $40+$10x

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1. We already know he has $40.

2. 10x represent the 10 dollars he is paid per month.

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3 years ago
In the Fall STA 2023 Beginning of the Semester Survey, students were asked how many parties they attended every week and how man
algol13

Answer:

A.58.81

Step-by-step explanation:

x = number of parties attended

y = number of text messages sent

The residual is the difference between the actual number of text messages sent (200) and the number of texts predicted by the regression model:

y=64.96+25.41x\\y=64.96+25.41*3\\y=141.19

The residual is:

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3 years ago
If a circle has a circumference of 200π what is its radius?
chubhunter [2.5K]

Answer:

31.83

Step-by-step explanation:

The circle would have a circumference of 31.83

4 0
3 years ago
When graphing a linear inequality, what does a dashed boundary line indicate?
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Step-by-step explanation:

6 0
3 years ago
Can anyone pls solve this.
OLga [1]

Answer:

3) \frac{(25)^{3/2} * (243)^{3/5}}{(16)^{5/4}*(8)^{4/3}}

=> \frac{(5^2)^{3/2}*(3^5)^{3/5}}{(2^4)^{5/4}*(2^3)^{4/3}}

=> \frac{5^3*5^3}{2^5*2^4}

=> \frac{5^6}{2^9}

4) \frac{3-2\sqrt{2} }{3+2\sqrt{2} }

Multiplying and dividing by conjugate 3-2\sqrt{2}

=> \frac{(3-2\sqrt{2})(3-2\sqrt{2}) }{(3+2\sqrt{2})(3-2\sqrt{2})}

=> \frac{9-6\sqrt{2}-6\sqrt{2} +8 }{9-8}

=> \frac{17-12\sqrt{2} }{1}

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a = 17, b = -12

7 0
3 years ago
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