Ask question

Ask question

All categories

3 years ago

8

6. Determine the income tax for a family of three (husband, wife, and child) if their adjusted gross income is $48,346 and their

itemized deductions are $10,345. Use $3,050 as the amount of each personal exemption.
A) $28,851
B) $39,195
C) $34,951
D) $38,001

1 answer:

Nataly [62]3 years ago

7 0

I believe A is your best answer choice.
I hope this helped!

You might be interested in

I need help plsss I will give u more points

lions [1.4K]

Answer:

The value of 0.9* 10² is <u>D</u><u>.</u><u>9</u><u>0</u><u>.</u>
<u>4</u><u>*</u><u>(</u><u>1</u><u>2</u><u>-</u><u>8</u><u>)</u><u>+</u><u>2</u><u>³</u>

4*4+2³
16+8
24

a.

<u>False</u><u> </u><u>:</u><u> </u><u>it</u><u> </u><u>is</u><u> </u><u>to</u><u> </u><u>add</u><u> </u><u>1</u><u>6</u><u>+</u><u>8</u>

<u>b</u><u>.</u>

<u>False</u><u> </u><u>:</u><u> </u><u>its</u><u> </u><u>8</u><u>.</u>

<u>c</u><u>.</u>

<u>True</u><u>.</u>

<u>d</u><u>.</u>

<u>False</u><u> </u><u>:</u><u> </u><u>its</u><u> </u><u>2</u><u>4</u><u>.</u>

<u>3</u><u>.</u>

<u>side</u><u> </u><u> </u> of cube [a]=2ft

volume of cube [V]=a³=2³=8ft³

<u>He</u><u> </u><u>needs</u><u> </u><u>1</u><u> </u><u>bag</u><u> </u><u>to</u><u> </u><u>buy</u><u>.</u><u>As</u><u> </u><u>its</u><u> </u><u>volume</u><u> </u><u>is</u><u> </u><u>equal</u><u>.</u>

7 0

2 years ago

How many times does 4 go into 24

il63 [147K]

Answer:6

4 multiplied by 6 is 24 so 6 is the answer

4 0

2 years ago

Read 2 more answers

angelina has a collection of nickels and dimes worth $4.65. if she has 70 nickels and dimes how many of each does she have?

Alex777 [14]

Answer:

47 Nickels And 23 Dimes

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Simplify 4 whole 2/7 + 5/7

tia_tia [17]

Answer:

1

Step-by-step explanation:

2/7+5/7=7/7=1 because 7/7 would be a 1 whole

4 0

2 years ago

Read 2 more answers

What is the 9th term of the following geometric sequence? 7/9,-7/3,7,-21,63 ??????

dmitriy555 [2]

Given:

The geometric sequence is:

$\dfrac{7}{9},\dfrac{-7}{3},7,-21,63,...$

To find:

The 9th term of the given geometric sequence.

Solution:

We have,

$\dfrac{7}{9},\dfrac{-7}{3},7,-21,63,...$

Here, the first term is:

$a=\dfrac{7}{9}$

The common ratio is:

$r=\dfrac{a_2}{a_1}$

$r=\dfrac{\dfrac{-7}{3}}{\dfrac{7}{9}}$

$r=\dfrac{-7}{3}\times \dfrac{9}{7}$

$r=-3$

The nth term of a geometric sequence is:

$a_n=ar^{n-1}$

Where, a is the first term and r is the common ratio.

Substitute $a=\dfrac{7}{9},r=-3,n=9$ to find the 9th term.

$a_9=\dfrac{7}{9}(-3)^{9-1}$

$a_9=\dfrac{7}{9}(-3)^{8}$

$a_9=\dfrac{7}{9}(6561)$

$a_9=5103$

Therefore, the 9th term of the given geometric sequence is 5103.

5 0

3 years ago