<span>If logc81=2 then c=9
</span>
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
Their are 3 numbers less than 4 on a die with 6 sides so 3 is 50% of 6 so then it should land on a number less than 4 50% of the 600 rolls to get 300
To find the he dividend per share of stock,we can divide the dividends by the total amount of
share:
120000÷40000
=$3
If Tim Worker owns 45 shares of stock, his share of the declared dividends would be:
3×45
=$135
Hope it helps!
Answer:
If Nina is N years old and Maryna is M years old the sum of their ages would be N+M
In 6 year from now they you would go the sum of their ages now times 6
You equation would be
6(N+M)
Step-by-step explanation: