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4 years ago

Mean (ul) = 510 and standard deviation (0) = 80

Mathematics

1 answer:

aliina [53]4 years ago

3 0

Answer:

Step-by-step explanation:

1. Use a calculator with distribution functions here. We're interested in finding the area under the standard normal curve to the right of 590, given that the mean is 510 and the standard deviation is 80. Note that 590 = 510 + 80, meaning that 590 is 1 standard deviation above the mean.

According to the Empirical Rule, 68% of data under a standard normal curve lies within 1 standard deviation of the mean. The area from the extreme left of this curve to x = 510 is 0.500, and the additional area under the curve from 510 to 590 is 34% of the total area, or 0.340.

Thus, the desired area is 0.500 + 0.340 = 0.840. This represents the desired probability.

2. What percentile is a score of 750? Find the number of standard deviations to the left of 750:

750 - 510

z-score = ------------------- = 24/8 = 3.00

The desired percentile is the area to the left of z = 3.00. Using a calculator, we find this area to be 0.9987. That 750 score is in the 99+ percentile.

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I'm giving brainliest to the most helpful answer. For 50 points:

Alenkinab [10]

Answer:

1) $\displaystyle\frac{5}{18}\approx27.78\%$

2) $\displaystyle\frac{4}{7}\approx57.14\%$

3) $\displaystyle \frac{13}{16}=81.25\%$

Step-by-step explanation:

We are given a two-way frequency table. Using the table, we will determine the probability for each case.

Question 1)

P(A Student With A Part Time Job Without A Car)

Using the first column, the total number of students that have a part time job is 78+30=108.

Likewise, using the first column, we can see that out of those 108 students, 30 do not have a car.

Hence, the probability that a student with a part time job without a car is:

$\displaystyle P=\frac{30}{108}=\frac{5}{18}\approx27.78\%$

Question 2)

P(No Car | Does Not Have A Part Time Job)

Remember that the vertical line means conditional probability.

So, we want the probability of a student having no car given that they do not have a part time job.

Using the second column, we can see that the total number of students that do not have a part time job is 18+24=42.

Likewise, using the second column, 24 do not have a car.

Hence, the probability that a student with a part time job without a car is:

$\displaystyle P=\frac{24}{42}=\frac{4}{7}\approx57.14\%$

Question 3)

P(Part Time Job | Car)

So, we want to probability of a student having a part time job given that they have a car.

Using the first row, the total students that have a car is 78+18=96.

And of those 96 students, 78 have a part time job.

Hence, the probability that a student with a car has a part time job is given by:

$\displaystyle P=\frac{78}{96}=\frac{13}{16}=81.25\%$

4 0

3 years ago

Find the area of the parallelogram( base= 2.5 in- height= 1 ft

murzikaleks [220]

the answer is 2.5

explanation: area= base x height
area=2.5 x 1 which is 2.5

8 0

3 years ago

Segment EG is an angle bisector of angle FGH. Noah wrote a proof to show that triangle HEG is congruent to triangle FEG. Noah's

tangare [24]

Answer:

Line 3 is incorrect; we don't know anything about the lengths of HG, FG, HE, and EF, so this line is not valid based on the given information.

Step-by-step explanation:

In the Noah's poof of the construction, segment EG would divide angle FGH into two equal parts, which makes line 2 to be valid. i.e <EGH ≅ <EGF. And it can also be observed that line 4 is a valid theorem in proving the congruent nature of triangles.

But line 3 is not valid because of the condition of the statement. Furthermore, segments FG, EG, HG, HE and FE may not be congruent. Thus, the condition of the statement in line 3 is incorrect.

8 0

3 years ago

The initial outlay or cost is $1,000,000 for a four-year project. The respective future cash inflows for years 1, 2, 3 and 4 are

trasher [3.6K]

Answer:

The Payback Period from non discounted cash flows is 2 Years and 8 months

Step-by-step explanation:

With an initial outlay of $1,000,000

and Cash inflows for 4 years consecutively of $500,000 + $300,000 + $300,000 + $300,000

Pay back Period = the Period where Initial Outlay minus Cash Inflows equal Zero

= 1,000,000 - 500,000 (yr 1) - 300,000 (yr 2) - 200,000 (2/3 of Year 3) = 0

Pay back Period therefore is equal to 2 years & 8 months.

3 0

4 years ago

On Friday ,537 people attended a play.for Saturdays matinee there were 812 people.about how many more people attended the play o

valkas [14]

812-536=275
275 more people attended the play.

4 0

4 years ago