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3 years ago

Steve has 20 marbles in a bag, all the same size and shape. There are 8 red,

1 answer:

3 0

50/50 chance of getting a yellow marble.

Explanation:

There are 10 yellow marbles in the bag, and the other half are other colors. This would create a 50/50 ratio.

I am honestly super rusty with probability but oh well...

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Solve the following system of equations: x − 2y = 6 2x − 4y = 10

sweet-ann [11.9K]

There are no solutions. These two equations never intersect

3 0

3 years ago

A dilation with a scale factor of 2 is applied to the image below. What is the length of the new image?

STatiana [176]

A dilation of factor k multiplies all lengths by k.

So, in your case, all lengths double. The new length is 4.

8 0

3 years ago

De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de

Sunny_sXe [5.5K]

Answer:

La masa del Sol es $2.509\times 10^{31}$ kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

$M \propto \frac{r^{3}}{T^{2}}$

$M = k\cdot \frac{r^{3}}{T^{2}}$ (Eq. 1)

Donde:

$r$ - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

$T$ - Período oribital del satélite, medido en días.

$k$ - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

$M$ - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

$\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }$

$\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}$ (Eq. 2)

Donde:

$T_{M}$ , $T_{E}$ - Períodos orbitales de la Luna y la Tierra, medidos en días.

$r_{E}$ , $r_{M}$ - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

$M_{S}$ , $M_{E}$ - Masas del Sol y la Tierra, medidos en kilogramos.

Si $M_{E} = 75.97\times 10^{24}\,kg$ , $T_{E} = 365.3\,d$ , $T_{M} = 27.3\,d$ , $r_{M} = 3.84\times 10^{5}\,km$ y $r_{E} = 1.496\times 10^{8}\,km$ , entonces tenemos que la masa del Sol es:

$M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}$

$M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)$

$M_{S} = 2.509\times 10^{31}\,kg$

La masa del Sol es $2.509\times 10^{31}$ kilogramos.

7 0

3 years ago

Question is in photo please help and not spam random stuff

salantis [7]

Answer:

I think the answer is

x=(z(m-cw))/wy

Step-by-step explanation:

Try to distribute and multiply the values and get the x alone on one side

3 0

3 years ago

Read 2 more answers

A dinner platter is in the shape of a regular decagon the platter has an area of 161 in.² and a side length of 4.6 inches what's

cupoosta [38]

Number of sides= 10
Side length= 4.6 ( or in this case base)

161 sq inches / 10 = 16.1 area of triangle.

Area of triangle =(base * height)/2

16.1=(4.6*h)/2
multiply 16.1 by 2 (cancels the dividing the 2)

32.2=4.6*h
divid 32.2 by 4.6

7 is the height of the triangle

5 0

3 years ago