Y= 2x -2 that’s the answer. you’re welcome.
SOLUTION - GIVEN = Sara has two bag with 60% & 28% peanut.
prove = How much the peanut is used to make 10 pound of 45%
peanut.
TO PROOF - Assume that
let x be the value of the peanut used by sara from the bag
60% peanut bag.
let ( 10 - x) be the value of peanut used by sara from 28% peanut
bag.
as given the bag become of the 10 pound which contain
45% of peanunt.
thus we have
0.60x + 0.28 ( 10 - x ) = 0.45 (10)
0.60x + 0.28 ( 10 -x ) = 4.5
0.60x + 2.8 - 0.28 x = 4.5
0.60x - 0.28x = 4.5 - 2.8
0.32x = 1.7
x = 5.3125 peanut is taken from the 60% bag.
& 4.6875 peanut from the 28% bag.
Basically just substitute
3(-2)-1-3(-2) = -6-1+6 = -1
The answer is -1.
<h3>Answer: d. w = -6</h3>
Answer:
A) sin θ = 3/5
B) tan θ = 3/4
C) csc θ = 5/3
D) sec θ = 5/4
E) cot θ = 4/3
Step-by-step explanation:
We are told that cos θ = 4/5
That θ is the acute angle of a right angle triangle.
To find the remaining trigonometric functions for angle θ, we need to find the 3rd side of the triangle.
Now, the identity cos θ means adjacent/hypotenuse.
Thus, adjacent side = 4
Hypotenuse = 5
Using pythagoras theorem, we can find the third side which is called opposite;
Opposite = √(5² - 4²)
Opposite = √(25 - 16)
Opposite = √9
Opposite = 3
A) sin θ
Trigonometric ratio for sin θ is opposite/hypotenuse. Thus;
sin θ = 3/5
B) tan θ
Trigonometric ratio for tan θ is opposite/adjacent. Thus;
tan θ = 3/4
C) csc θ
Trigonometric ratio for csc θ is 1/sin θ. Thus;
csc θ = 1/(3/5)
csc θ = 5/3
D) sec θ
Trigonometric ratio for sec θ is 1/cos θ. Thus;
sec θ = 1/(4/5)
sec θ = 5/4
E) cot θ
Trigonometric ratio for cot θ is 1/tan θ. Thus;
cot θ = 1/(3/4)
cot θ = 4/3
