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exis [7]
3 years ago
14

What's the difference of 8 and c

Mathematics
1 answer:
Vlada [557]3 years ago
4 0

Answer:

do you know what the number for c is?

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I NEED HELP ASAPPPPP ​
soldier1979 [14.2K]

Answer:

y=55 degrees x=125 degrees

Step-by-step explanation:

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Please answer quickly!!!
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3 years ago
Marta is solving the equation S = 2πrh + 2πr^2 for h. Which should be the result?
olga_2 [115]

Answer:

h = \frac{S}{2πr} - r


Step-by-step explanation:

The question requires you to make h the subject of the formula.

S = 2πrh + 2πr²

subtract 2πr² on both sides.

S - 2πr² = 2πrh - 2πr² -  2πr²

S - 2πr² = 2πrh

Dividing both sides by  2πr

(S -  2πr²)/2πr =  2πrh/ 2πr

h = \frac{S}{2πr} - r


7 0
3 years ago
Read 2 more answers
What is the answer for this -12n - (-13n)=
Ksenya-84 [330]

Answer:

n

Step-by-step explanation:

-12n - (-13n) = -12n +13n = 1n

8 0
3 years ago
Suppose that p is the probability that a randomly selected person is left handed. The value (1-p) is the probability that the pe
solmaris [256]

Answer:

a) 1/2

b) 250

Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for p such that 1000p(1-p) is maximized. Once we have that p, we can easily find the answer to part b.

Finding the value that maximizes 1000p(1-p) is the same as finding the value that maximizes p(1-p), just on a smaller scale. So, we really want to maximize p(1-p). To do this, we will do a trick called completing the square.

p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4.

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of p such that the inner part of the square term is equal to 0.

p-1/2=0\\p=1/2.

So, the answer to part a is \boxed{1/2}.

We can then plug 1/2 into the equation for p to find the answer to part b.

1000(1/2)(1-1/2)=1000(1/2)(1/2)=1000*1/4=250.

So, the answer to part b is \boxed{250}.

And we're done!

3 0
3 years ago
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