How can I prove that a^(m+n)=a^m*a^n

1 answer:

7 0

I've got it down to m+n=m*n but that doesn't seem to help. I'm still working

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olga_2 [115]

No, because since this decimal doesn't stop, it doesn't count as terminating

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Leviafan [203]

The answer to that is x=8

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Y_Kistochka [10]

X is the input and y is the output, "more" indicates addition, so 11 more than the input equals x + 11. Answer: y = x + 11

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