Answer:
First, use the equation of the trend line to find the IQ that is expected by the GPA. Next, use the other equation of the trend line to find the SAT that is predicted by the IQ.
Step-by-step explanation:
have a great day!
Answer:
52 ft
Step-by-step explanation:
For each chord, the product of segment lengths is a constant. We can find that constant as the product of the segment lengths of the bisected chord:
(24 ft)·(24 ft) = 576 ft^2
Then the missing segment length (DX) of the diameter chord is ...
DX·(36 ft) = 576 ft^2
DX = (576 ft^2)/(36 ft) = 16 ft
So, the total length of the diameter chord is ...
DX +XL = 16 ft + 36 ft
DL = 52 ft
_____
We know DL is a diameter because the perpendicular bisector of any chord intersects the center of the circle.
Answer:
.75 would be your answer to your question!
I hope this really answered your question and i'm really happy to help!
Step-by-step explanation:
So you would take the $9.50 + .75 and you will get the answer $10.25
Answer:
The equation would be 2,250 - 120<em>m</em>
Answer:
True
Step-by-step explanation:
A six sigma level has a lower and upper specification limits between
and
. It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:
.
The probability of defects is:

Well, the defects present in a six sigma level and a five sigma level are, respectively:
Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>
[1]
[2]
Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.