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kykrilka [37]
2 years ago
8

Plz help asp.................

Mathematics
1 answer:
Vsevolod [243]2 years ago
5 0

Answer:

J,L M,O R,H

Step-by-step explanation:

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Given these two data sets, IQ-GPA and IQ-SAT, how would you predict Justin’s SAT score based on his GPA? Explain.
daser333 [38]

Answer:

First, use the equation of the trend line to find the IQ that is expected by the GPA. Next, use the other equation of the trend line to find the SAT that is predicted by the IQ.

Step-by-step explanation:

have a great day!

8 0
2 years ago
Read 2 more answers
Help with this question, please!
uranmaximum [27]

Answer:

52 ft

Step-by-step explanation:

For each chord, the product of segment lengths is a constant. We can find that constant as the product of the segment lengths of the bisected chord:

(24 ft)·(24 ft) = 576 ft^2

Then the missing segment length (DX) of the diameter chord is ...

DX·(36 ft) = 576 ft^2

DX = (576 ft^2)/(36 ft) = 16 ft

So, the total length of the diameter chord is ...

DX +XL = 16 ft + 36 ft

DL = 52 ft

_____

We know DL is a diameter because the perpendicular bisector of any chord intersects the center of the circle.

5 0
3 years ago
Keelin’s hourly rate went from $9.50 per hour to $10.25 per hour. What is the percent increase?
bazaltina [42]

Answer:

.75 would be your answer to your question!

I hope this really answered your question and i'm really happy to help!

Step-by-step explanation:

So you would take the $9.50 + .75 and you will get the answer $10.25

3 0
3 years ago
Please help!
NNADVOKAT [17]

Answer:

The equation would be 2,250 - 120<em>m</em>

7 0
3 years ago
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
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