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ale4655 [162]
3 years ago
7

The probability that it will be at least 70°on Tuesday is 0.65. If it is at least 70°, there is a 0.8 chance that Mrs. Collins w

ill hold her book club outside. If it is not at least 70°, then there is only a 0.1 chance that the book club will be held outside. What is the probability that Mrs. Collins will not hold her book club outside on Tuesday? 0.13 0.445 0.555 0.835
Mathematics
1 answer:
Zielflug [23.3K]3 years ago
7 0
P(> or =70) =0.65
P(Collins inside) =0.80
P(not 70) = 1-P(70) =>0.35
P(Collins inside) = 0.1
Then P(70 AND Collin inside) .65 x .8 =0.52
P( not 70 AND Collin Outside = 0.35 x 0.1=0.035
TOTAL Possibility [(70 AND Inside) OR (not 70 AND Outside):
=0.52 + 0.034 =0.555


 

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anyanavicka [17]
3 is less than 5, so rounded to the nearest ten is 360.

6 is greater than 5, so rounded to the nearest hundred, our answer is 400.
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You are creating a decorative rope that is at least 20 feet long. You do not have enough 6 inch beads to make the rope, so you w
Inessa05 [86]

You can use at most 24 beads that are 10 inches long to decorate the rope.

Step-by-step explanation:

Given,

Length of rope = 120 feet

1 foot = 12 inches

20 foot = 20*12 = 240 inches

Length of bead = 10 inches

Let,

x represents the number of beads used on rope.

As the rope is 240 inches long, therefore, the total length of beads cannot exceed 240 inches.

Length of each bead*Number of beads ≤ length of rope

10*x\leq 240\\10x\leq 240

Dividing both sides by 10

\frac{10x}{10}\leq \frac{240}{10}\\x\leq 24

You can use at most 24 beads that are 10 inches long to decorate the rope.

Keywords: inequality, division

Learn more about inequalities at:

  • brainly.com/question/10250188
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#LearnwithBrainly

4 0
3 years ago
The value of y varies directly with x and y = 4.5 when x = 0.5. find y when x = 10
Pepsi [2]
So what you asked this is what I got

x(y) = 4.5

If x= 0.5 then 

0.5(y) = 4.5
y=9

x(y) = 4.5

10(y) = 4.5
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hope this helps :)





3 0
3 years ago
Choose one of the factors of 500x3 + 108y18
sammy [17]

Answer:

Option C

Therefore, one of the factors of 500x^3 +108y^\left (18\right ) is (5x+3y^6).

Step-by-step explanation:

Given: 500x^3 +108y^\left (18\right )

the common factor from 500x^3 and 108y^\left (18\right ) is 4.

therefore, 4\cdot \left ( 125x^3+27y^\left (18\right ) \right )

4\cdot \left ( (5x)^3+(3y^6)^3 \right))

Now, use the formula for above expression: (a^3+b^3)=(a+b)(a^2-ab+b^2)

here, a=5x and b=3y^6

( (5x)^3+(3y^6)^3 \right))=(5x+3y^6)(25x^2-15xy^6+9y^12)

Therefore, we have

500x^3 +108y^\left (18\right )=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right )  \right )

Therefore, one of the factors of 500x^3 +108y^\left (18\right ) is (5x+3y^6).








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