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3 years ago

Please help ASAP!

Mathematics

2 answers:

ser-zykov [4K]3 years ago

7 0

The area of this rectangular monitor is 850 cm². So it's C.

34 cm * 25 cm = 850 cm²

The answer can't be 850 cm because area is in cm²... Perimeter is in cm alone...

Ainat [17]3 years ago

5 0

25 • 34

850

The answer is C, 850 cm squared.

Hope this helps!

If it does then I would appreciate it if you could make me brainliest.

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A'Reana earns a weekly allowance for doing chores around the house and for keeping all of her grades above a C. During a particu

JulsSmile [24]

Answer:

Answer: A'Reana's weekly allowance is $100

Step-by-step explanation:

Backward Solution

To solve some problems, we can work backward, using the inverse operations, to arrive at the solution.

The problem explains a sequence of expenses A'Reana does with her weekly allowance. In the end, she had $37.50.

That final balance came when she last spent $7.50 on a pizza. Thus, before that, she had $37.50+$7.50=$45

This balance is half of her previously remaining money. The other half was spent on a new shirt. Thus she had 2*$45=$90.

Those $90 were left after she gave $10 to her friend Taylor, thus, the initial money was $90+$10 = $100

Answer: A'Reana's weekly allowance is $100

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3 years ago

2) Find the slope of the line

Morgarella [4.7K]

Your answer would be x= 2

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3 years ago

Select the correct answer.

DedPeter [7]

Answer: The correct option is (D) (4, -6).

Step-by-step explanation: Given that the areas of the triangles ADC and DCB are in the ratio 3 : 4.

We are to find the co-ordinates of point C.

From the diagram, we note that

the co-ordinates of point A and B are A(1, -9) and B(8,-2).

So, the length of the line segment AB, calculated by distance formula, is

$AB=\sqrt{(1-8)^2+(-9+2)^2}=\sqrt{49+49}=7\sqrt2.$

Now, area of ΔADC is

$A_{ABC}=\dfrac{1}{2}\times AC\times CD,$

and area of ΔDCB is

$A_{DCE}=\dfrac{1}{2}\times BC\times CD.$

According to the given information, we have

$A_{ADC}:A_{DCB}=3:4\\\\\\\Rightarrow \dfrac{A_{ADC}}{A_{DCE}}=\dfrac{3}{4}\\\\\\\Rightarrow \dfrac{\frac{1}{2}\times AC\times CD}{\frac{1}{2}\times BC\times CD}=\dfrac{3}{4}\\\\\\\Rightarrow \dfrac{AC}{BC}=3:4.$

So, the point C divides the line segment AB internally in the ratio 3 : 4.

We know that

if a point divides a line segment with end-points (a, b) and (c, d) internally in the ration m : n, then its co-ordinates are

$\left(\dfrac{mc+na}{m+n},\dfrac{md+nb}{m+n}\right).$

Since point C divides the line segment AB with end-points A(1, -9) and B(8, -2) internally, so the co-ordinates of point C will be

$\left(\dfrac{3\times 8+4\times 1}{3+4},\dfrac{3\times (-2)+4\times (-9)}{3+4}\right)\\\\\\=\left(\dfrac{28}{7},\dfrac{-42}{7}\right)\\\\\\=(4, -6).$

Thus, the co-ordinates of point C are (4, -6).

Option (D) is correct.

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Answer:

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Step-by-step explanation:

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