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Korolek [52]
3 years ago
13

Eighteen and seventy-five hundredths in standard notation

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
4 0

Answer:

18.75

Step-by-step explanation:


postnew [5]3 years ago
3 0

Answer:

-3/4

Step-by-step explanation:

-3-(-3/4) /4-1

=-3+3/4 /3

=-9/4 /3

=-3/4

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Solve. -7x=x^2+12 help
Nat2105 [25]

Hey There!

The answer to your problem is x=-3 or x=-4 both answers are correct!

<u>Step 1: Subtract x²+12 from both sides.</u>

−7x−(x²+12)=x²+12−(x²+12)

−x²−7x−12=0

<u>Step 2: Factor left side of equation.</u>

(-x-3)(x+4)=0

<u>Step 3: Set factors equal to 0.</u>

-x-3=0 or x+4=0

<u>Get your answer:</u>

x=-3 or x=-4

3 0
4 years ago
PLEASE HELP, URGENT!!
EastWind [94]

Answer:

I don't get it

Step-by-step explanation:

7 0
4 years ago
If each interior angle of a regular polygon measures ​120 , how many sides does the polygon​ have?
KatRina [158]

Answer:

the ans is 6 sides i guess

3 0
3 years ago
Read 2 more answers
The lengths of the sides of a triangle are 3, 3, and the square root 3. Can the triangle be a right triangle?
Readme [11.4K]
First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
 
If the base and height were each 3, then the hypotenuse would need to be:

3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24

This is larger than sqrt(3), so this cannot be a right triangle.


If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46

This is larger than 3, this cannot be a right triangle.

The answer is b) no.





8 0
4 years ago
Read 2 more answers
If T is the midpoint of segment RS then, Segment RT is congruent to segment TS..<br> Help please!!!!
omeli [17]

Answer:

Definition of Midpoint

Step-by-step explanation:

Since T is the midpoint then it is equadistant from R to T and T to S

3 0
3 years ago
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