Lowest value: 2
Highest value: 19
Median: 8
Lower quartile: 6
Upper quartile: 14
Range: Highest value - Lowest value = answer
Range: 19 - 2 = 17
Interquartile range: Upper quartile - Lower quartile = answer
(IQR) interquartile range = 14 - 6 = 8
So the answer to your question would be 8 :)
~hope this helps, have a good day/afternoon/night~
Answer:
see below
Step-by-step explanation: 5 23 15 03
f(x) = g(x) + 4 find g(x) for f(x) = 3x + 2
sub f(x) = 3x + 2 into f(x) = g(x) +4
3x + 2 = g(x) + 4
3x + 2 - 4 = g(x) + 4 - 4
3x - 2 = g(x)
Best Answer: <span> y=18x^2+9x+14
y=18(x^2+(1/2)x + 1/16) + 14 - 9/8
y = 18(x + 1/4)^2 + 103/8
For y = a*(x - h)^2 + k, (h, k) the vertex
Your vertex: (- 1/4, 103/8)
Equation of axis of symmetry is x = (x-coordinate of vertex) OR x = - 1/4
y-intercept is y-value when x = 0, y = 14
x-intercept(s) do not exist for this upward opening parabola whose vertex y-value is above the x-axis.
The minimum of the function is the y-value of the vertex, 103/8.
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Seems like Dizzle was in too much of a hurry and Jeff just copied Dizzle's answer.
The correct way of doing what dizzle TRIED to do:
For y = a*x^2 + b*x + c, the vertex occurs when x = - b / (2*a)
y=18x^2+9x+14
a = 18
b = 9
- b / (2*a) = - (9) / (2*18) = - 9 / 36 = - 1/4
Take that value for x, evaluate function at that value to get y.
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Was so giddy about dizzle's faux pas that I originally did this work. May as well share it:
x-intercept(s) can be found by setting function equal to zero and solving:
y = 18(x + 1/4)^2 + 103/8
0 = 18(x + 1/4)^2 + 103/8
18(x + 1/4)^2 = - 103/8
(x + 1/4)^2 = - 103/144
x + 1/4 = +/- i*sqrt(103)/12
x = - 1/4 +/- i*sqrt(103)/12 OR x = [- 3 +/- i*sqrt(103)] / 12
These are the roots of the equation f(x) = 0
Since the roots are complex, there are no x-intercepts. The function is entirely above the x-axis. </span>
Answer:
B.
Step-by-step explanation:
Answer:
-7
Step-by-step explanation:
