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Bad White [126]
2 years ago
10

Gina has 440 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed are

a. What is the maximum area?
Mathematics
1 answer:
podryga [215]2 years ago
6 0

Answer:

<h3>THerefore, the area would be 12,100 square yards</h3>

Step-by-step explanation:

Let the length be x and the width be y

The perimeter of a rectangle is give as ; 2 ( L + B) , that is

We know the perimeter formula would be 440=2x+2y. And the area will be A=x*y

We can to take the derivative of the area formula to find where it is a max but we must first substitute something in from the first formula so we only have one variable.

440-2x=2y

220-x=y

A=(x)*(220-x)

A=220x-x^2

Now we take the derivative:

A'=220-2x (set equal to 0 and solve)

0=220-2x

2x=220

x=110 

Then when we plug this into the perimeter formula, we can solve for y

440=2x+2y

440=2(110)+2y

440=220+2y

220=2y

y=110

So both the length and width are 110 yards, and the area would be 12,100 square yards

<h3>THerefore, the area would be 12,100 square yards</h3>

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A. A product has a probability of 60% showing up in warehouse A, and 80% in warehouse.
Alex_Xolod [135]

Answer:

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Step-by-step explanation:

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Same as above

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4 0
3 years ago
the area of a rectangle is 54x^9y^8 square yards if the length of the rectangle is 6x^3y^4 yards what expression represents the
Vinvika [58]
The area of a rectangle is given by:
 A = (w) * (l)
 Where,
 w: width
 l: long
 Substituting values we have:
 (54x ^ 9y ^ 8) = (w) * (6x ^ 3y ^ 4)
 Clearing w we have:
 w = (54x ^ 9y ^ 8) / (6x ^ 3y ^ 4)
 Rewriting:
 w = (9 * x ^ 6y ^ 4)
 Answer:
 
the length of the rectangle is:
 
w = (9 * x ^ 6y ^ 4)
5 0
2 years ago
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