Answer:
18. g= -3
19. x= -1
20. n= 3
21. p= -1
22. d= -3
23. a= 5
Step-by-step explanation:
how to solve the variable (using 18 as an example)
step 1: simplify both sides of the equation.
20+g+g=14
(g+g)+(20)=14(combine like terms)
2g+20=14
2g+20=14
step 2: subtract 20 from both sides.
2g+20−20=14−20
2g=−6
step 3: divide both sides by 2.
2g/2 = -6/2
Answer:
y=2x+10
Step-by-step explanation:
In line equations its helpful to write your line in the form y = ax + b. This helps because a is always the gadient of the line and b is always the y intercept.
In this case it is y=2x+3
All parallel lines have the same gradient. The gradient of this line = 2.
If the line crosses the x axis at x=-5, then when x =-5 y = 0.
If you put all this in the form y =ax + b you get 0 = 2(-5) +b
So all you need to do to find b is rearrange. b = 10.
Therefore your line has gradient 2 and y intercept 10.
y = 2x + 10
Answer:
2
Step-by-step explanation:


<em>good luck, i hope this helps :)</em>
Answer:
f(x) has a larger growth rate
f(x) is always greater than g(x)
Step-by-step explanation:
f(x) = 2/5 x
g(x) = -2x
the slope of f(x) when graphed is 2/5 x, which is a positive value making it a larger growth rate than g(x) and it also will always be greater since the value of f(x) is positive
therefore the correct true statements are:
f(x) has a larger growth rate, and f(x) is always greater than g(x)


so, the percentage of the rate is 0.185, what's that as a percentage? well, 0.185 * 100, 18.5%.