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ozzi
3 years ago
14

Illustrate the distributive property to solve 144/8

Mathematics
1 answer:
AURORKA [14]3 years ago
4 0

Answer:

8 (19) or  8 (18 +1)

Step-by-step explanation:

Distributive property means to distribute.

HCF of 144 and 8.

=> 8 is the HCF of 144 and 8

8 (18 + 1)

=> 8 (19)

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Express the relation {(-3, 4), (-1, 2), (3, -4), (2, -2)} as a table and a graph. What is the domain and range?
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A triangle has sides with lengths of 6 inches, 8 inches is it a right triangle? ​
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3 years ago
If two boxes of cereal and a jug of milk cost $8.50, and three boxes of cereal and two jugs of milk cost $14.00, how much does a
Citrus2011 [14]

Answer:

$3

Step-by-step explanation:

Let c represent the cost of a box of cereal and let m represent the cost of a jug of milk.

Create a system of equations:

2c + m = 8.5

3c + 2m = 14

Solve by elimination by multiplying the top equation by -2:

-4c - 2m = -17

3c + 2m = 14

Add them together and solve for c:

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2 years ago
What’s the domain and range of:<br> log(√(2x-1) + 3 )<br> Please explain how you got it too!!
Radda [10]

Two main facts are needed here:

1. The logarithm \log x, regardless of the base of the logarithm, exists for x>0.

2. The square root \sqrt x exists for x\ge0.

(in both cases we're assuming real-valued functions only)

By (2) we know that \sqrt{2x-1} exists if 2x-1\ge0, or x\ge\dfrac12.

By (1), we know that \log(\sqrt{2x-1}+3) exists if \sqrt{2x-1}+3>0, or \sqrt{2x-1}>-3. But as long as the square root exists, it will always be positive, so this condition will always be met.

Ultimately, then, we only require x\ge\dfrac12, so the function has domain \left[\dfrac12,\infty).

To determine the range, we need to know that, in their respective domains, \sqrt x and \log x increase monotonically without bound. We also know that x=\dfrac12 at minimum, at which point the square root term vanishes, so the least value the function takes on is \log3. Then its range would be [\log3,\infty).

3 0
3 years ago
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