1)

2)5x^2-45/2y-6
7)6x^5+4x^4-x^3/2
8)5
3)x^2-4x+6/x-2
4)23/5x
5)-2x+9/x^2-5x+6
6)x=-28/3,x
≠-3
also im a 12th grader in connections academy? and you?
Answer:
It is 12
Step-by-step explanation:
Without any more information, the first term can be any number.
Let <em>a</em> be the first term in the geometric progression, and let <em>r</em> be the common ratio between consecutive terms. Then
<em>a</em> + <em>ar</em> + <em>ar</em> ² + <em>ar</em> ³ + <em>ar</em> ⁴ + <em>ar</em> ⁵ = 9 (<em>a</em> + <em>ar</em> + <em>ar</em> ²)
<em>ar</em> ³ + <em>ar</em> ⁴ + <em>ar</em> ⁵ = 8 (<em>a</em> + <em>ar</em> + <em>ar</em> ²)
<em>r</em> ³ + <em>r</em> ⁴ + <em>r</em> ⁵ = 8 (1 + <em>r</em> + <em>r</em> ²)
<em>r</em> ³ (1 + <em>r</em> + <em>r</em> ²) = 8 (1 + <em>r</em> + <em>r</em> ²)
<em>r</em> ³ = 8
<em>r</em> = 2
Now with this ratio, the sum of the first six terms is
<em>a</em> (1 + <em>r</em> + <em>r</em> ² + <em>r</em> ³ + <em>r</em> ⁴ + <em>r</em> ⁵) = <em>a</em> (1 - <em>r</em> ⁶)/(1 - <em>r</em>) = 63<em>a</em>
while the sum of the first three terms is
<em>a</em> (1 + <em>r</em> + <em>r</em> ²) = <em>a</em> (1 - <em>r</em> ³)/(1 - <em>r</em>) = 7<em>a</em>
and of course 63<em>a</em> = 9 • 7<em>a</em>, and this is true for any <em>a</em>.
The value of the expression sec (-π) is equal to -1 if the given expression is undefined.
As given in the question,
Given expression: sec (-π)
Standard position of unit circle: -π is representing semicircle with terminal point on negative x-axis with coordinates (-1, 0)
Hypotenuse = √ (-1)² + 0²
= 1
Value of the expression is given by
sec α = Hypotenuse / Base (x-coordinate)
⇒sec(-π) = 1 / -1
⇒sec(-π) = -1
Therefore, the value of the expression sec (-π) is equal to -1.
Learn more about expression here
brainly.com/question/14083225
#SPJ1