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tamaranim1 [39]
3 years ago
6

Janie receives an allowance of $3 per week. In addition, she can earn $2 for each chore she does. This week, she wants to earn e

nough money to buy a CD for $13. Janie can do fractions of chores.
Write an inequality to determine the number of chores, cc, Janie must do this week to earn enough money to buy a CD.
Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
7 0

Answer:

n ≥ 5

Step-by-step explanation:

The money that Janie earns (E) must be greater than or equal to the cost (c) of the CD.

In symbols,

        E ≥ c

2n + 3 ≥ 13     Subtract 2 from each side

     2n ≥ 10      Divide each side by 2

       n ≥ 5

Janie must do five or more chores to buy the CD.

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Plz help me with this
Diano4ka-milaya [45]

A is 95t+25.  This is the simplest form, but the way you do it is that 25t+15+20t+10+50t=9t+25.


6 0
3 years ago
The game commission observes the fish population in a stream and notices that the number of trout increases by a factor of 1.5 e
just olya [345]

Answer:

A - f(t)=80(1.5)^t

B - Graph given below

C - Number of trouts in 5th week are 607.2

D - Population of trouts will exceed 500 on the 5th week.

Step-by-step explanation:

We are given that,

The number of trout increases by a factor of 1.5 each week and the initial population of the trout is observed to be 80.

Part A: So, the explicit formula representing the situation is,

f(t)=80(1.5)^t, where f(t) represents the population of trouts after 't' weeks.

Part B: The graph of the function can be seen below.

It can be seen that the function is an exponential function.

Part C: It is required to find the number of trouts in the 5th week.

So, we have,

f(5)=80(1.5)^5

i.e. f(5)=80\times 7.59

i.e. f(5) = 607.2

Thus, the number of trouts in 5th week are 607.2

Part D: We are given that the trout population exceeds 500.

It is required to find the week in which this happens.

So, we have,

50

i.e. (1.5)^t>\frac{500}{80}

i.e. (1.5)^t>6.25

i.e. t\log 1.5>\log 6.25

i.e. t\times 0.1761>0.7959

i.e. t>\frac{0.7959}{0.1761}

i.e. t > 4.5

As, t represents the number of weeks. So, to nearest whole, t = 5.

Thus, the population of trouts will exceed 500 on the 5th week.

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Answer:

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Step-by-step explanation:

$1,200/8=150 150*7=1050

I might be wrong tho

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