Let
x,y, and z the long sides of the triangle
we know that
x+y+z=170 ft------> equation 1
x/y=25/14----> y=14x/25------> equation 2
y/z=14/12-----> equation 3
x/z=25/12----> z=12x/25------> equation 4
substitute equation 2 and equation 4 in equation 1
x+[14x/25]+[12x/25]=170------> multiply by 25 both sides
25x+14x+12x=4250
51x=4250
x=4250/51
x=250/3
y=14x/25------> y=(250/3)*(14/25)----> y=140/3
z=12y/14-----> (140/3)*12/14----> z=40
Using Heron's formula,
Area of the triangle = √s (s-a) (s-b) (s-c)
where s is the semiperimeter
s=170/2-----> s=85 ft
Area=√85*[85-250/3]*[85-140/3]*[85-40]
Area=9.22*[1.67]*[38.33]*[45]------> Area=26558.21 ft²
the answer is
26558.21 ft²
The answer should be 31, if I’m doing this correctly.
6(3)2-5 (multiply 6 and 3, you get 18)
18(2)-5 (multiply 18 and 2, you get 36)
36-5 (subtract 36 and 5)
31
Answer:
294cm²
Step-by-step explanation:
You didn’t convert from meters to centimeters.
It was 2.94m².
That equals 294cm².
B. Is the right answer
First you have to take the common elements then use an identity/formula to get the rest
x^3 - 3x^2 + x-3
x^2 (x-3) +1 (x-3)
(x^2 +1) (x-3)
(x-1)(x+1)(x-3) {using a^2-b^2 on x^2-1^2}