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3 years ago

What symbol do you use for square root on pc?

Mathematics

2 answers:

blondinia [14]3 years ago

8 0

For this case we must find the values of "a" and "b" that make the expressions equivalent:

We have:

$\sqrt {\frac {126xy ^ 5} {32x ^ 3}} =$

We take common factor "2" from the numerator and denominator:

$\sqrt {\frac {2 * (63xy ^ 5)} {2 * (16x ^ 3)}} =$

Eliminating common factors of numerator and denominator:

$\sqrt {\frac {63y ^ 5} {16x ^ 2}} =$

So, we have that the values of a and b are:

$a = 16\\b = 2$

Answer:

$a = 16\\b = 2$

Note: To write square root on pc we use sqrt

EleoNora [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Type in "sqrt .... " or click on the "omega" icon below for a list of built-in math characters, including "√"

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Use order of operation to solve 4[2.5+3(20+7)]

telo118 [61]

334 is the answer to the question

7 0

3 years ago

Read 2 more answers

A group of 75 math students were asked whether they like algebra and whether they like geometry. A total of 45 students like alg

tatiyna

Let x be the number of students that like both algebra and geometry. Then:

1. 45-x is the number of students that like only algebra;

2. 53-x is the number of students that like only geometry.

You know that 6 students do not like any subject at all and there are 75 students in total. If you add the number of students that like both subjects, the number of students that like only one subject and the number of students that do not like any subject, you get 75. Therefore,

x+45-x+53-x+6=75.

Solve this equation:

104-x=75,

x=104-75,

x=29.

You get that:

29 students like both subjects;
45-29=16 students like only algebra;
53-29=24 students like only geometry;
24+6=30 students do not like algebra;
16+6=22 students do not like geometry.

The correct choice is D.

5 0

3 years ago

Read 2 more answers

Can you help me solve this proof please?

blagie [28]

So.. Wouldn't the angles be 90 degrees since they are perpendicular to each other?ABD and CBD are probably connected to each other by line BD so AC must form a straight line. AC is now perpendicular to BD, but I'm not sure how to prove AD and DC are congruent lines, unless lines are drawn to connect those points..

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3 years ago

PLSSS PLSSS I NEED HELPP

suter [353]

Answer:

Step-by-step explanation:

Perpendicular (p) = 8

base(b) = 7

Tan A = p/b

tan A = 8/7

A = tan ^-1(8/7)

A = 48.81°

4 0

3 years ago

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

Marina86 [1]

Answer:

(a) 0.94

(b) 0.20

Step-by-step explanation:

From a population (Bernoulli population), 90% of the bearings meet a thickness specification, let $p_1$ be the probability that a bearing meets the specification.

So, $p_1=0.9$

Sample size, $n_1=500$ , is large.

Let X represent the number of acceptable bearing.

Convert this to a normal distribution,

Mean: $\mu_1=n_1p_1=500\times0.9=450$

Variance: $\sigma_1^2=n_1p_1(1-p_1)=500\times0.9\times0.1=45$

$\Rightarrow \sigma_1 =\sqrt{45}=6.71$

(a) A shipment is acceptable if at least 440 of the 500 bearings meet the specification.

So, $X\geq 440.$

Here, 440 is included, so, by using the continuity correction, take x=439.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{339.5-450}{6.71}=-1.56$ .

So, the probability that a given shipment is acceptable is

$P(z\geq-1.56)=\int_{-1.56}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}}=0.94062$

Hence, the probability that a given shipment is acceptable is 0.94.

(b) We have the probability of acceptability of one shipment 0.94, which is same for each shipment, so here the number of shipments is a Binomial population.

Denote the probability od acceptance of a shipment by $p_2$ .