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Korolek [52]
3 years ago
10

Can you help me solve this proof please?

Mathematics
1 answer:
blagie [28]3 years ago
7 0
So.. Wouldn't the angles be 90 degrees since they are perpendicular to each other?ABD and CBD are probably connected to each other by line BD so AC must form a straight line. AC is now perpendicular to BD, but I'm not sure how to prove AD and DC are congruent lines, unless lines are drawn to connect those points..
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Which size bag of cat food shown in table has the lowest unit price?
motikmotik
The 40 oz and $8.00 i think

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3 years ago
The table shows the number of games a team won and lost last season. Wins and Losses Last Season Number of Games Wins 24 Losses
sergiy2304 [10]

Answer:

The table shows the number of games a team won and lost last season is explained below in details.

Step-by-step explanation:

"Greg is creating a simulation, using previous year’s wins and losses, to foretell the team's conclusion.

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Probability is the ratio of the probability that an incident will take place. The more eminent is the probability of an incident, there are likewise outcomes that the game will happen.

4 0
3 years ago
Read 2 more answers
THERE ARE 3 BAGS OF APPLES WEIGHING A TOTAL OF 22 1/2 POUNDS. TWO OF THE BAGS WEIGH 6 3/8 POUNDS AND 3 1/4 POUNDS. HOW MUCH DOES
Mkey [24]
I wasn't going to click on this one, but the all-caps enthralled me and hypnotized me.

first off, let's change all the mixed fractions to "improper" and proceed from there, keep in mind that if we subtract the two bags' weight from the total, what's leftover is the 3rd bag's weight.

\bf \stackrel{mixed}{22\frac{1}{2}}\implies \cfrac{22\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{45}{2}}
\\\\\\
\stackrel{mixed}{6\frac{3}{8}}\implies \cfrac{6\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{51}{8}}
\\\\\\
\stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}\\\\
-------------------------------\\\\

\bf \stackrel{\textit{sum of the two bags}}{\cfrac{51}{8}+\cfrac{13}{4}}\impliedby \textit{our LCD is 8}\implies \cfrac{(1)51+(2)13}{8}
\\\\\\
\cfrac{51+26}{8}\implies \cfrac{77}{8}\\\\
-------------------------------\\\\
\stackrel{total}{\cfrac{45}{2}}~-~\stackrel{two~bags}{\cfrac{77}{8}}\impliedby \textit{our LCD is again 8}\implies \cfrac{(4)45-(1)77}{8}
\\\\\\
\cfrac{180~~-~~77}{8}\implies \cfrac{103}{8}\implies \stackrel{third~bag}{12\frac{7}{8}}
3 0
4 years ago
What is the slope between the points (-3, 7) and (-5, 4)​
IrinaVladis [17]

Answer:

3/2

Sorry for the bad handwriting.

4 0
4 years ago
Please help du tomorrow
Leokris [45]
The perimeter of the first figure is 34 cm and the area is 64 cm².
The perimeter of the second figure is 38 cm and the area is 60 cm².
The perimeter of the third figure is 30 cm and the area is 36 cm².
The perimeter of the fourth figure is 72 cm and the area is 200 cm².
The perimeter of the fifth figure is 30 cm and the area is 36 cm².

To find the perimeter of each, we add the area of all sides.  For the first figure, the missing sides are 1 cm and 6 cm.  To find the area, we have two rectangles whose dimensions are 6x10 and 1x4.

For the second figure, the missing sides are 4 cm and 3 cm.  To find the area, we have two rectangles whose dimensions are 4x12 and 3x4.

For the third figure, the missing sides are 3 cm, 3 cm and 8 cm.  To find the area, we have two rectangles whose dimensions are 4x3 and 3x8.

For the fourth figure, the missing sides are 10 cm, 10 cm, 6 cm and 6 cm.  To find the area, we have two squares whose dimensions are 10x10.

For the fifth figure, the missing sides are 3 cm and 9 cm.  To find the area, we have two rectangles whose dimensions are 3x6 and 6x3.
3 0
3 years ago
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